What are the zeros of the quadratic function f(x) = 6x^2 + 12x - 7?
1 answer:
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The equation that represents the line that is perpendicular is
3y + 5x = -42
The standard equation of a line in point-slope form is expressed as:
- m is the slope of the lne
- (x1, y1) is any point on the line.
- Given the equation y = 3/2x + 1, the slope of the line is 3/5
- The s<u>lope of the line perpendicular</u> is -5/3
Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:
Hence the equation that represents the line that is perpendicular is
3y + 5x = -42
Learn more on equation of a line here:brainly.com/question/19417700
Answer:
The slope is 0
Step-by-step explanation:
(2-2) divided by (6-5) equals to 0 which is the Slope