What are the zeros of the quadratic function f(x) = 6x^2 + 12x - 7?
1 answer:
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Answer:
Step-by-step explanation:
A quadratic function has the formula ax² + bx + c
- To determine if a graph will be narrow or wide, the leading coefficient, a, will be the factor that determines this
- The greater the coefficient, the narrower the parabola
- The lesser the coefficient, the wider the parabola
Here all of the functions are in the form ax²
- In
, our "a" term is
- In y = -2x², our "a" term is -2
- In y = -3x², our "a" term is -3
- In
, our "a" term is
We can eliminate the two functions with the negative coefficients because they are much smaller than the two functions with the fractions as coefficients, and will therefore open much wider.
We can now compare the two remaining functions, and
- Giving the two fractions common denominators would turn them into
and
- The equation with the larger fraction will be the parabola that is the narrowest. In this case, it is the
.
- Therefore,
will have the narrowest graph
Answer:
The correct option is;
y - P = two fifths (x - Q).
Step-by-step explanation:
The equation for the old route is given as follows;
Therefore, we have;
The slope of the equation of the old route = 2/5
Given that the new route is parallel to the old route and passes through the point (Q, P), the slope of the new route = 2/5 and the equation of the new route in slope and intercept form can be written as follows;
y - P = 2/5×(x - Q)
Therefore, the correct option is y - P = two fifths (x - Q).