A)
s = sweater
j = jeans
Equations:
4s + 2j = 140
2s + 3j = 150
B)
4s + 2j = 140
2s + 3j = 150
Multiply (-2) to the second equation
-2 (2s + 3j = 150)
-4s - 6j = -300
Now you have the equations:
4s + 2j = 140
-4s - 6j = -300
-----------------------------add
-4j = -160
j = 40
4s + 2(40) = 140
4s + 80 = 140
4s = 60
s = 15
The cost for a sweater is $15 and the cost for a jean is $40
We used the elimination method to solve the system of equations.
C)
Each pair of jean, she will buy 3 sweaters so total = 40 + 3(15) = $85
Total cost for 1 pair of jeans and 3 sweaters = $85
If she has $225 the
$225 / $85 = 2.64
2 jeans = 2 x 40 = $80
6 sweaters = 6 x $15 = $90
So She can only buy 2 jeans and 6 sweaters
Answer:
12.54
Step-by-step explanation:
5>0
<h3>Answer:</h3>
64
<h3>Explanation:</h3>
6+4= 10
Then reverse the digits of 64, and you have 46
64-46= 18
Answer:
The original price of the item was $83
Step-by-step explanation:
Answer:
40%
Step-by-step explanation:
14/35 members voted him. Lets convert this into a percentage:
14/35 * 100% = 14/35 *100/100 = 40%
<em>I hope this helps! :)</em>
