If f(1) = 160 and f(n + 1) = –2f(n), what is f(4)?

2 answers:

8 0

Hello,

f(1)=160
f(2)=160*(-2)
f(3)=160*(-2)²
f(4)=160*(-2)^3=-1280

f(n)=160*(-2)^(n-1)

6 0

Answer:

-1280

Step-by-step explanation:

just took the test

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