Answer:
Price of advance ticket: 15$
Price of same-day ticket: $40
Step-by-step explanation:
Let 
be the price of one advance ticket and 
the cost of one same day ticket.
We know that the combined cost of one advance ticket and one same-day ticket is $55, so
equation (1)
We also know that 20 advance tickets and 35 same-day tickets cost $1700, so
equation (2)
Now, let's solve our system of equations step-by-step:
step 1. Solve for in equation (1)
equation (3)
step 2. Replace equation (3) in equation (2)
equation (4)
step 3. Replace equation (4) in equation (3)
We can conclude that the price of one advance ticket is $15 and the price of one same-day ticket is $40.
Answer:
124
Step-by-step explanation:
558/4.5=124
Answer:
1.37
Step-by-step explanation:
hope this can help u
9×7=63
63÷2=31.5
31.5×4=126
7×7=49
126+49=175
175 is the answer
In the given question it is important to take note of every minute details that are given in the question. using these details the answer to the given question can be easily reached.
Let us assume the common ratio to be x.
Then
x + 9x = 81
10x = 81
x = 81/10
= 8.1
A s we already know that the ratio of chaperones to students is 1:9
Then
The number of chaperones = 1 * 8.1
= 8.1
So 8.1 chaperones were there in total. I hope you have got the answer you were looking for.
