A=LW
192=(13+x)((9+x)
192=117+22x+x^2 (subtract 192 from both sides)
x^2+22x-75+0 (factor)
(x+25)(x-3)=0
so x=-25 or 3
Check work
since we are adding x it can only be the positive solution so x=3 so the new dimensions are:
L=13+3=16m
W=9+3=12
check: 16*12=192 so the answer is correct hope this helped

7 0

3 years ago

How do i add <img src="https://tex.z-dn.net/?f=-%5Cfrac%7B3%7D%7B10%7D%20plus%20%5Cfrac%7B2%7D%7B3%20%7D%5C%5C" id="TexFormula1"

antoniya [11.8K]

$-\dfrac{3}{10}+\dfrac{2}{3}=\dfrac{2}{3}+\left(-\dfrac{3}{10}\right)=\dfrac{2}{3}-\dfrac{3}{10}\\\\\text{We must find the common denominator.}\\\\Multiples\ of\ 3:0,\ 3,\ 6,\ 9,\ 12,\ 15,\ 18,\ 21,\ 24,\ 27,\ \boxed{30},\ 33,\ 36,...\\\\Multiples\ of\ 10:\ 0,\ 10,\ 20,\ \boxed{30},\ 40,\ 50,\ 60,...\\\\\dfrac{2}{3}=\dfrac{2\cdot10}{3\cdot10}=\dfrac{20}{30}\\\\\dfrac{3}{10}=\dfrac{3\cdot3}{10\cdot3}=\dfrac{9}{30}\\\\\dfrac{2}{3}-\dfrac{3}{10}=\dfrac{20}{30}-\dfrac{9}{30}=\dfrac{20-9}{30}=\dfrac{11}{30}$