Answer:
The slope of the line that contains diagonal OE will be = -3/2
Step-by-step explanation:
We know the slope-intercept form of the line equation
y = mx+b
Where m is the slope and b is the y-intercept
Given the equation of the line that contains diagonal HM is y = 2/3 x + 7
y = 2/3 x + 7
comparing the equation with the slope-intercept form of the line equation
y = mx+b
Thus, slope = m = 2/3
- We know that the diagonals are perpendicular bisectors of each other.
As we have to determine the slope of the line that contains diagonal OE.
As the slope of the line that contains diagonal HM = 2/3
We also know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line.
Therefore, the slope of the line that contains diagonal
OE will be = -1/m = -1/(2/3) = -3/2
Hence, the slope of the line that contains diagonal OE will be = -3/2
There is no solution for the first one
if you eliminate y you get 2 equations
-13x - 13z = -25
-13x - 13x = -15
- there is no solution to theses
a23 means the element in the second row and the 3rd column
so its -5
<span>The answer: b. translated according to the rule (x, y) → (x + 8, y + 2) and reflected across the x-axis
If you make the drawing of the situation you realize the you need a reflection through the x-axis, but first you need to translate the polygon several units to the left and upward.
You can see that all the x-coordinates have increased 8 units, so the solution has to include x + 8.
Also, you see that you have to move the polygon 2 units upward before doing the reflection so the solution has to include y + 2.
So, the answer is (x,y) ---> (x + 8, y + 2) and then reflection across the x-axis.
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Step-by-step explanation:
g(x)=3x+5
g(-3)=3(-3)+5
=-9+5
=-4
