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katen-ka-za [31]
4 years ago
7

Hey! Can someone check my answers?

Mathematics
1 answer:
Andrew [12]4 years ago
3 0
The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}
Since x^{a}* x^{b}  =x^{a+b}, then x^{9}= x^{3}* x^{6}

Back to our expression:
4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+  5y ^{6}*1=5 y^{6} (4y ^{3} +1)
The greatest common factor is thus 5 y^{6}


Q2. The answer is <span>D. 12xy^2
</span>
12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}
We will use the rule  x^{a}* x^{b} =x^{a+b} to factorise the exponents:
12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)
The greatest common factor is thus 12xy^{2}
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All the fourth-graders in a certain elementary school took a standardized test. A total of 81% of the students were found to be
Dvinal [7]

Answer:

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

Step-by-step explanation:

Let's define the events:

L: The student is proficient in reading

M: The student is proficient in math

The probabilities are given by:

P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64

P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17

The probability that a student is proficient in mathematics, but not in reading is, 0.10.

The probability that a student is proficient in reading, but not in mathematics is, 0.17

5 0
4 years ago
3x-2y=18 solve for x
Usimov [2.4K]

x=6

hope i helped!!! :)

5 0
3 years ago
Use the disruptive property to simplify (-5-c)(-1)<br> A-5 -c <br> B 5+c<br> C -5+c <br> D 5-c
Nady [450]

Answer:

B). 5+c

Step-by-step explanation:

we need to distribute -5-c to -1

we can do it as its written or we can flip it around and still get the same answer. When we distribute we multiply the varable or number out parenthesis with the ones in the paretesis  

so -5 *-1=5

-c*-1=c

these two are positive now so they are no longer being subtracted from each other...

your answer is

B). 5+c

3 0
3 years ago
Subtract.<br> (6x + 5) - (x + 3)<br> A. 5x + 2<br> B. 6x + 2<br> C! 6x + 8<br> D. 5x + 8
Natali [406]

Answer: 5x + 2

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Not sure need help please​
Varvara68 [4.7K]

Answer:

Explanation and problem 1 solved below.

Step-by-step explanation:

The quadrants are numbered this way:

Quadrant 1: upper right

Quadrant 2: upper left

Quadrant 3: lower left

Quadrant 4: lower right

Signs of coordinates in the quadrants:

x-coordinate is positive in Q1 and Q4

x-coordinate is negative in Q2 and Q3

y-coordinate is positive in Q1 and Q2

y-coordinate is negative in Q3 and Q4

1. (-1, 5)

x is negative, so it is Q2 or Q3

y is positive, so it is Q1 or Q2

The quadrant in common is Quadrant 2

Answer: quadrant 2

4 0
3 years ago
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