Answer: The correct answer is- B) Okazaki fragments are made on the lagging strand but not on the leading strand.
DNA replication is a biological process in which two identical replica of DNA are produced from single original DNA molecule through an enzyme called DNA polymerase.
The strands of double helical DNA are first separated ( with the help of helicase enzyme) so that the template DNA strands are exposed. DNA is synthesised in 5' to 3' direction.
Leading strand ( whose template strand is 3' to 5') is synthesized in continuous manner as DNA polymerase moves along the direction of replication folk.
Whereas lagging strand ( whose template strand is 5' to 3') is synthesized in a discontinuous manner as it requires multiple primers to synthesise the DNA. It generates small fragments of DNA called okazaki fragments.
The boundary between conducting zone and respiratory zone structures occurs at the terminal bronchiole/respiratory bronchiole junction. The major respiratory structures span the nasal cavity to the diaphragm. Functionally, the respiratory system can be divided into a conducting zone and a respiratory zone. The conducting zone of the respiratory system includes the organs and structures not directly involved in gas exchange. The gas exchange occurs in the respiratory zone.
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Answer:
The solubility of any substance in water depends on its polarity. The polar molecule dissolves more easily in the water than the non polar molecule. Amino acids have different polarity at different pH.
(a) (Lys-Ala)3 : The (Lys-Ala)3 contain more positive charge and highly polar the at pH 7 as compared with the (Gly)20 that remains uncharged and has less polarity.
(b) (Glu)20 :This amino acids negatively charged at pH 7 and highly polar than the (Phe-Met)3 which is non polar or less polar and hence least soluble in water.
(c) (Asn-Ser-His)5 is highly polar at pH 3 as compared with the (Ala-Asp-Gly)5 that contains the carboxylate groups of Asp residues that are partially neutral. The (Asn-Ser-His)5 contains = the imidazole groups of His residues are fully polar and soluble in water.
(d) (Asn-Ser-His)5 is polar at pH 6.0 because both have polar side chains Ser but (Asn-Ser-His)5 is only partially partially protonated due to the His side chains. Thus, (Asn-Ser-His)5 is more soluble in water.
