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LiRa [457]
3 years ago
7

Divide. Assume that no denominator equals zero.

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
3 0
So,

We simply invert and multiply.
\frac{8d^{3} * 24}{6c * c^{3}d^{4}}

Re-arrange the numbers so that they are easier to understand.
\frac{(24)(8)(d^{3})}{(6c)(c^{3})(d^4)}

Factor.
\frac{(2^5)}{(c^4)(d)}\ or\  \frac{32}{c^{4}d}

Cancel out 1's.

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Hey i know this question is linked to Pythagorean theorem but i am still confused. So, please help me if you can ❤️
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Step-by-step explanation:

From Pythagorean theorem, one of the sides can be determined as x^2 + y^2 =8^2

or y = (8^2 - x^2)^(1/2)

we can write the perimeter P as

P = 2x + 2y ---> 20 = 2x + 2(8^2 - x^2)^(1/2)

Dividing by 2, we get

10 = x + (8^2 - x^2)^(1/2)

Move the x to the other side,

10 - x = (8^2 - x^2)^(1/2)

Take the square of both sides to get rid of the radical sign:

(10 - x)^2 = 8^2 - x^2

Move everything to the left and expand the quantity inside the parenthesis:

x^2 + (100 - 20x + x^2) - 64 = 0

2x^2 - 20x + 64 = 0

or

x^2 - 10x + 32 = 0

Now we can see that a = -10 and b = 32

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