Step-by-step explanation:
1. You already got the first step, where D is the midpoint of AC and AB is congruent to BC, since it's given.
2. AD will be congruent to DC, via the definition of a midpoint (a midpoint is the middle point of a line segment, and it splits the segment into two congruent parts)
3. BD is equal to BD, via reflexive property. ( It's a shared side between the two triangles)
4. that means that ΔADB ≅ΔCDB via SSS rule.
5. ∠ABD ≅∠CDB by CPCTC (corresponding parts of congruent triangles are congruent)
Hope this helps! :)
5a(b-c)=d. Here, we are trying to isolate the variable b.
Divide both sides by 5a: b-c=d/(5a)
Add c to both sides: b=
I HOPE THE ABOVE INFORMATION WILL HELP YOU.
Thank you.
<em>Teddy</em><em> </em><em>lover</em><em> </em><em>❤</em><em>❤</em>
Answer:
Step-by-step explanation:
I haven't got time to do all these by I'll give you the method in each case.
You have to make the x or y term equal (or 1 term + and other -) in both equations before adding or subtracting.
A . Multiply equation 2 by 2 and subtract (to eliminate x)
- don't forget to multiply EACH TERM by 2.
B. Multiply equation 2 by -2 and add.
C. Multiply equation 1 by 3 and equation 2 by 2 ( this will give -6y and +6y in the resulting equations ) so you then add to eliminate y.
D. Multiply equation 1 by 13 and equation and equation 2 by 2 to eliminate x then add.
