All categories

3 years ago

What is the differance between constructing a square and construciting an eguilateral triangle

Mathematics

2 answers:

lutik1710 [3]3 years ago

7 0

Answer:

A square is a box looking like figure with four sides in which all sides have equal length and make an angle (90⁰) with eachother. Equilateral triangle is a triangle(consisting three sides) in which the sides have equal length and making an angle of 60⁰ with each other. Hope this helps.

Aleksandr-060686 [28]3 years ago

3 0

Answer:

One has 4 sides and one has 3 sides

Step-by-step explanation:

a square has 4 sides and an equilateral triangle has 3 sides

You might be interested in

Find the value of x.<br> If necessary, you may learn what the markings on a figure indicate.<br> 74°

marissa [1.9K]

Answer:

x = 61

Step-by-step explanation:

Left hand triangle containing 1 angle of 74

Label the other angle opposite the marked side also as 74

Find the third angle. Call it y.

y + 74 + 74 = 180 Combine like terms

y + 148 = 180 Subtract 148 from both sides.

y = 180 - 148

y = 32

=============

Now work with the triangle on the right.

label the angle making up the right angle = z

32 + z = 90 These two angles are complementary = 90

32 - 32 + z = 90 - 32 Subtract 32 from both sides

z = 58 Use 58 wherever you see z

x + x + z = 180 Substitute

2x + 58 = 180 Subtract 58 from both sides

2x = 122 Divide by 2

x = 61

5 0

3 years ago

Read 2 more answers

Translate this phrase into an algebraic expression:

krek1111 [17]

Jesus is the lord above all

3 0

3 years ago

Let n be a natural number. Show that 3 | n3 −n

Vladimir [108]

Let $n=1$ . Then $n^3-n=1^3-1=0$ . By convention, every non-zero integer $n$ divides 0, so $3\vert n^3-n$ .

Suppose this relation holds for $n=k$ , i.e. $3\vert k^3-k$ . We then hope to show it must also hold for $n=k+1$ .

You have

$(k+1)^3-(k+1)=(k^3+3k^2+3k+1)-(k+1)=(k^3-k)+3(k^2+k)$

We assumed that $3\vert k^3-k$ , and it's clear that $3\vert 3(k^2+k)$ because $3(k^2+k)$ is a multiple of 3. This means the remainder upon divides $(k+1)^3-(k+1)$ must be 0, and therefore the relation holds for $n=k+1$ . This proves the statement.

4 0

2 years ago

I need a Quotient and a remainder for this polynomial long division

Elina [12.6K]

2x+6 3/x+7 I attached an image of my work on here