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3 years ago

How many terms are in the algebraic expression 2y+3x-5x^2-9?

Mathematics

2 answers:

Artist 52 [7]3 years ago

7 0

There are 4 terms...

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

There are four terms in this expression.

Step-by-step explanation:

The algebraic expression is

$2y+3x-5x^2-9$

In this expression, the variable is x and y and the constant is -9

Below are the terms of the expression

2y , 3x , -5x^2 and -9

Therefore, there are four terms in this expression.

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5a please :) I don't know the formula

Naddika [18.5K]

S.A = (2×area of base) + area of lateral faces
Area of lateral faces = area of base × height

Area of lateral faces = 19×4×8=608
S.A = (2×19×4)+608
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3 0

4 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago

Write each of the following expressions without using absolute value: |z−6|−|z−5|, if z<5

abruzzese [7]

Answer:

The answer is 1.

Step-by-step explanation:

Given the expression:

$|z-6|-|z-5|,\ if\ z$

To find:

The expression without absolute value.

Solution:

First of all, let us learn about the absolute value function:

$y = f(x) = |x| =\left \{ {{x\ if\ x>0} \atop {-x\ if\ x$

i.e. value is x if x is positive

value is -x if x is negative

Here the given expression contains two absolute value functions:

$|z-6|$ and $|z-5|$

Using the definition of absolute value function as per above definition.

$|z-5| =\left \{ {{(z-5)\ if\ z>5} \atop {-(z-5)\ if\ z$

$|z-6| =\left \{ {{(z-6)\ if\ z>6} \atop {-(z-6)\ if\ z$

Now, it is given that z < 5 that means z will also be lesser than 6 i.e. z < 6

So, given expression $|z-6|-|z-5|,\ if\ z$ will be equivalent to :

$-(z-6) - (-(z-5))\\\Rightarrow -z+6 +z-5 = \bold{1}$

So, the expression is equivalent to 1.

6 0

3 years ago

Find the value of x. A.18 B.15 C.16 D.19 PLEASE HELP!!!!!

In-s [12.5K]

Answer:

x = 19

Step-by-step explanation:

123°+3x = 180°

3x = 180°-123°

3x = 57

x = 57/3

x = 19

The reason why we use 123° + 3x = 180° because both are adjacent angles. Adjacent angles add up to 180°

7 0

3 years ago

Solving a system of linear equations using the substitution method. 5x+4y=-26 5-x=-6y

yan [13]

Solve for x in 2nd equation
times -1 both sides
x-5=6y
add 5
x=6y+5

sub

5(6y+5)+4y=-26
30y+25+4y=-26
34y+25=-26
minus 25 both sides
34y=-51
divide both sides by 34
y=-3/2
sub back

x=6y+5
x=6(-3/2)+5
x=-18/2+5
x=-9+5
x=-4

(-4,-3/2) is solution

5 0

3 years ago

Read 2 more answers