Answer: ![b(t(h))=135h^2+180h+125](https://tex.z-dn.net/?f=b%28t%28h%29%29%3D135h%5E2%2B180h%2B125)
Step-by-step explanation:
Given: The number of bacteria, B, in a refrigerated food is given by the function
, where t is the temperature of food in degrees Fahrenheit.
The function
gives the temperature, t, of the food h hours after being removed from the refrigerator.
Now, the number bacteria in the food in h hours is given by:-
![b(t(h))=15(3h+4)^2-60(3h+4)+125\\=15(9h^2+16+24h)-180h-240+125\\=135h^2+240+360h-180h-240+125\\=135h^2+180h+125](https://tex.z-dn.net/?f=b%28t%28h%29%29%3D15%283h%2B4%29%5E2-60%283h%2B4%29%2B125%5C%5C%3D15%289h%5E2%2B16%2B24h%29-180h-240%2B125%5C%5C%3D135h%5E2%2B240%2B360h-180h-240%2B125%5C%5C%3D135h%5E2%2B180h%2B125)
So, The number bacteria in the food in h hours is given by:
![b(t(h))=135h^2+180h+125](https://tex.z-dn.net/?f=b%28t%28h%29%29%3D135h%5E2%2B180h%2B125)
Rate of change of profit for this period is $2750 per month
<em><u>Solution:</u></em>
Given that,
Profit of $6500 in January and $17,500 in May
<em><u>To find: Rate of change</u></em>
Since,
January is the first month of the year (1) while May is the fifth month (5)
<em><u>Therefore, we get two points</u></em>
(1, 6500) and (5, 17500)
Using these points we can find the rate of change in profit for this time period
<em><u>The rate of change using the following formula:</u></em>
![m = \frac{y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_2-y_1%7D%7Bx_2-x_1%7D)
Here from the points,
![(x_1, y_1) = (1, 6500)\\\\(x_2, y_2) = (5, 17500)](https://tex.z-dn.net/?f=%28x_1%2C%20y_1%29%20%3D%20%281%2C%206500%29%5C%5C%5C%5C%28x_2%2C%20y_2%29%20%3D%20%285%2C%2017500%29)
<em><u>Therefore, rate of change is given as:</u></em>
![m = \frac{17500-6500}{5-1}\\\\m = \frac{11000}{4}\\\\m = 2750](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B17500-6500%7D%7B5-1%7D%5C%5C%5C%5Cm%20%3D%20%5Cfrac%7B11000%7D%7B4%7D%5C%5C%5C%5Cm%20%3D%202750)
Thus rate of change of profit for this period = $2750 per month
A random sample (Sample 1) of the Mercedes's average driving speed (km/h) is: 120, 142, 142, 165, 132, 130, 156, 136, 167, 139,
ziro4ka [17]
The median of Mercedes' speed is 144 km/h.
The median of Audi's speed is ~133,6 km/h.
3/4. The line is aming to 3 sorry im not that smart
Answer:
f(-2) = 3
Step-by-step explanation:
Look at the graph when x = -2, f(-2) = 3