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How do you find the original price after a discount. The sales price is 55.50 and the percent of discount is 75%.

Arte-miy333 [17]

Well first we know that 55.50 is 25% so I guess multiply it by 3 to get the full price equalling nearly 166 which is closest to 165, so that’d be my answer. Sorry if wrong.

6 0

2 years ago

Read 2 more answers

What is the range of the equation

a_sh-v [17]

The range of the equation is $y>2$

Explanation:

The given equation is $y=2(4)^{x+3}+2$

We need to determine the range of the equation.

Range:

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

$y=2 \cdot 4^{x+3}+2$

This can be written as $y=2^{1+2(x+3)}+2$

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

$x=2^{1+2(y+3)}+2$

Solving for y, we get;

$x-2=2^{1+2(y+3)}$

Applying the log rule, if f(x) = g(x) then $\ln (f(x))=\ln (g(x))$ , then, we get;

$\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)$

Simplifying, we get;

$(1+2(y+3)) \ln (2)=\ln (x-2)$

Dividing both sides by $\ln (2)$ , we have;

$2 y+7=\frac{\ln (x-2)}{\ln (2)}$

Subtracting 7 from both sides of the equation, we have;

$2 y=\frac{\ln (x-2)}{\ln (2)}-7$

Dividing both sides by 2, we get;

$y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}$

Let us find the positive values for logs.

Thus, we have,;

$x-2>0$

$x>2$

The function domain is $x>2$

By combining the intervals, the range becomes $y>2$

Hence, the range of the equation is $y>2$

7 0

3 years ago

Help .. 3(x+2)=5x+1-2x+5

Hunter-Best [27]

Answer:

All real numbers are solutions

Step-by-step explanation:

Let's solve your equation step-by-step

3(x+2)=5x+1−2x+5

Step 1: Simplify both sides of the equation

3(x+2)=5x+1−2x+5

(3)(x)+(3)(2)=5x+1+−2x+5(Distribute)

3x+6=5x+1+−2x+5

3x+6=(5x+−2x)+(1+5)(Combine Like Terms)

3x+6=3x+6

Step 2: Subtract 3x from both sides

3x+6−3x=3x+6−3x

6=6

Step 3: Subtract 6 from both sides

6−6=6−6

0=0

8 0

3 years ago

Write an equation of a line that passes through (5,

enyata [817]

Answer:

y = 1/5x - 11

Step-by-step explanation:

perpendicular to a line means we flip the slope to opposite of what it is

in other wrds, since your slope is -5, your new slope for the line perpendicular to it would be 1/5.

Now we just use the same equation to find the y-intercept, which is b.

y = mx + b; m is your slope and b is your y intercept.

use the points given; (5, -10).

-10 = 1/5(5) + b

-10 = 1 + b

-11 = b

now put your equation together since you have all the pieces

y = 1/5x - 11

3 0

3 years ago

Please Identify the congruent triangles in the figure.

Tpy6a [65]

The missing steps are each right angles and $\angle R \cong \angle O$ .

Solution:

Step 1: Given data:

$\overline {P Q} \cong \overline{M N}$

$\overline{Q R} \cong \overline{N O}$

$\overline{P R} \cong \overline{M O}$

Step 2: In the two polygons,

$\angle Q =90^\circ$ and $\angle N =90^\circ$

$\angle Q \cong \angle N$ (Each right angle)

Step 3: Given

$\angle P \cong \angle M$

Step 4: By third angle theorem,

If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.

$\angle R \cong \angle O$

Step 5: By the definition of congruent polygons,

If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.

Hence $\Delta P Q R \cong \Delta M N O$ .

Therefore the missing steps are each right angles and $\angle R \cong \angle O$ .

5 0

3 years ago

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