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Darya [45]
2 years ago
6

5/3 divided by (-6/7).Write your answer in simplest form.Please please Help me!! ​

Mathematics
2 answers:
lana [24]2 years ago
7 0

Answer:

-1  17/18

Step-by-step explanation:

I solved this.

oksian1 [2.3K]2 years ago
4 0

Answer:

-\frac{35}{18}

Step-by-step explanation:

\frac{5}{3} ÷ -\frac{6}{7} is the same as \frac{5}{3} × -\frac{7}{6}

Multiply across:

5 x 7 = 35

3 x 6 = 18

Applying the negative sign, we get:

-\frac{35}{18}

Since we cannot simplify any further, -35/18 is out final answer.

Hope this helps!

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Simplify 5t + (t - 3) - [(7t + 5) - (8 - 3t)].<br> -4t<br> 4t<br> -10t<br> 10t
Ne4ueva [31]

Answer:

(A)   - 4t

Step-by-step explanation:

5t + (t - 3) - [(7t + 5) - (8 - 3t)] =5t + (t - 3) - [7t + 5 - 8 + 3t] =

= 5t + (t - 3) - [10t -3 ] = 5t + t - 3 - 10t + 3 = - 4t

6 0
4 years ago
Please help ASAP 25 pts + brainliest to right/best answer
-Dominant- [34]

Answer:

d  5 =9^ y

Step-by-step explanation:

log9 (5) = y

If we have loga(b) =c   then it becomes a^c =b

So 9^y = 5

I also think

Raise each side to the 9

9^(log9 (5)) =9^ y

That will get rid of the log9

5 =9^ y

6 0
3 years ago
Please help me with this equation: 1+2+3...+60
prisoha [69]
Is this A.P ?
Please specify mate
7 0
3 years ago
Read 2 more answers
Help me I give crown :--(((
torisob [31]

Answer:

The answer is 170 meters

Step-by-step explanation:

hope it helps :)

7 0
3 years ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

  E(150) = 6500 -50(150) = 6500 -7500 = -1000 . . . . 150 days is beyond the capacity of the system

The supply is not enough to last for 5 months.

3 0
3 years ago
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