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3 years ago

Please simplify..... Attached

Mathematics

2 answers:

Kazeer [188]3 years ago

7 0

Answer:

your answer should be...

(B.) -18

Hope this helps!

insens350 [35]3 years ago

5 0

Answer:

The answer is 3rd point.

Step-by-step explanation:

You can simplify the bracket first,

(-1/2×√2)

= (-1/2×√2)

(-6√18)

= -6(√2×9)

= -6×3√2

= -18√2

Finally, you can expand it :

(-1/2√2)(-18√2)

= (-1/2 × -18)(√2 × √2)

= 9 × 2

= 18

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Please Help! The graph of y=f(x) is shown below. What are all of the real solutions of f(x)=0? (Picture of graph included)

qwelly [4]

Answer:

(7, 0), (-8, 0), (0, 0)

Step-by-step explanation:

y = f(x) = 0

the real solutions are the ones that cross the x-axis because when a point is on the x-axis, its y coordinate will be 0.

=> (7, 0), (-8, 0), (0, 0)

6 0

3 years ago

Work out m and c for the line: 3 y + 6 x = − 3

Usimov [2.4K]

Answer:

m is -2 and c is -1

Step-by-step explanation:

• Let's first phrase out the general equation of a line

${ \rm{y = mx + c}}$

m is the slope
c is the y-intercept

[ remember that a general line equation must be in slope - intercept form as shown above ]

• from our question, we are given the equation;

${ \rm{3y + 6x = - 3}}$

• let's make y the subject in order to make the equation in slope - intercept format.

→ remember to apply "subject making knowledge"

${ \rm{3y = - 3 - 6x}} \\ \\ { \rm{3y = - 6x - 3}} \\ \\ { \rm{ \frac{3y}{3} = \frac{ - 6x}{3} - \frac{3}{3} }} \\ \\ { \boxed{ \rm{y = - 2x - 1}}}$

• The above boxed equation is now a general equation. Let's extract out slope, m and y-intercept, c

${ \rm{m \: \dashrightarrow \: - 2}} \\ \\ { \rm{c \: \dashrightarrow \: - 1}}$

8 0

3 years ago

Find the volume of a square pyramid whose base has a perimeter of 25 inches and a height of 9 inches. Round all answers to the n

lana66690 [7]

Answer:

B i would say

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.

$h(t)=-48t -16t^2$

$h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2$

$h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})$

$h(-\frac{3}{2})=72-4*9$

$h(-\frac{3}{2})=72-36$

$h(-\frac{3}{2})=36$

Therefore, the maximum height of the ball is 36 feet.

3 0

3 years ago

Question content area top

BigorU [14]

The volume of the slice is 40 in³. The volume of the remaining cake would be 197.014 in³.

<h3>What is a regular hexagon?</h3>

A regular hexagon can be defined as a closed shape consisting of six equal sides and six equal angles.

Here we have two regular hexagons

one top small hexagon cake with a side of length = 3 in, height = 3 in

One big hexagon cake, side of length = 4 in, Height = 4 in

A slice cut such that it removes a side segment is equivalent to an equilateral triangle with a side

length = length of hexagon side

The length of the side of the removed equilateral triangle side

Top small cake slice triangle side = 3 in.

Area of surface of small slice = 1/2 x b x h = 1/2 x 3 x 3 x sin 60

= 9√3/ 4

The volume of a small slice

= Area of surface small slice × Height of small cake

= 9√3/ 4 x 3

= 11. 69

Big cake slice triangle side = 4 in.

Area of the surface of big slice = 1/2 x 4 x 4 x sin 60

= 4√3

The volume of big slice = Area of the surface of big slice × Height of big slice

= 16√3

= 28

The total volume of slice = Volume of small slice + Volume of big slice

Total volume of slice = 12 in³ +28 in³ = 40 in³

For the small cake,

the remaining volume = 5 x 11.69 = 58.45

For the big cake

the remaining volume = 5 x 27.71 = 138.56

Total volume remaining cake

= 58.45 in³ + 138.56 in³ = 197.014 in³

a = Length of side

h = Height of hexagon

The volume of each slice is,

= a^2 x h x √3/4

For the small cake, we have

a = 3 in.

h = 3 in.

The volume of small slice = a^2 x h x √3/4

= 9 x 3 x √3/4

= 27√3/4

For the big cake, we have

a = 4 in.

h = 4 in.

Volume of big slice = a^2 x h x √3/4

= 16 √3

The total volume of slice = Volume of small slice + Volume of a big slice

Total volume of slice = 27√3/4 + 16 √3

The total volume of the slice = 39404 in³.

Learn more about hexagon;

brainly.com/question/16025389

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3 0

2 years ago