Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
we are given
Firstly, we will find all possible factors of 144
we can also write as
now, we can put exponent to over entire term
now, we can replace 144
now, sqrt will get cancelled with square
and we get
now, we can simplify it
.............Answer
Answer:
[see below]
Step-by-step explanation:
I used a graphing program to graph the given system. I also graphed the points given.
Options B's choice lies in the double shaded area, so it would be a solution to the system.
See the graph attached!
Hope this helps you!
You could try, www.2020tahermath/polygongmlearn.org
Answer:
17%
Step-by-step explanation:
it's basically just 17/100 which would be 17%
