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juin [17]
2 years ago
5

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

Mathematics
1 answer:
insens350 [35]2 years ago
6 0
ITS B. The range is the stuff in the right circle. So its 245
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The two values are positive 9 and negative 9
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3 years ago
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Please solve with explanation (high points)
IgorLugansk [536]

So, we know that:

A=\dfrac{1}{2}ab\\P=a+b+c\\a^2+b^2=c^2

We also know that (a+b)^2=a^2+2ab+b^2. We will use that fact to find c in terms of A and P.

A=\dfrac{1}{2}ab\Rightarrow 2ab=4A\\P=a+b+c\Rightarrow a+b=P-c

Therefore:

(P-c)^2=c^2+4A\\P^2-2cP+c^2=c^2+4a\\2cP=P^2-4A\\c=\dfrac{P^2-4A}{2P}

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2 years ago
What is the length of the hypotenuse of a right triangle if each of the two legs is 4 units? square root of 8 units 4 units squa
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By the Pythagoras theorem, in a right triangle with the sides being a and b,

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Hypotenuse = √2 * √16

Thus, hypotenuse = 4√2


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3 years ago
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On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5).
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Answer:

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Since you can plug the first 2 coordinates into the slope equation (\frac{y_{2}-y_{1}}{x_{2} -x_{1} }) you will get 4 for the slope so for the equation for the parallel line you would get y=4x+4 and since the x=4 you could plug that in and you would get y=20 and x=4

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Answer:

Step-by-step explanation:

Alright so we are going to solve

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x≥5

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3 years ago
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