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Sati [7]
3 years ago
9

During his tennis career in singles​ play, John won 4 fewer tournament A titles than tournament B titles and 2 more tournament C

titles than tournament B titles. If he won 13 of these titles​ total, how many times did he win each​ one?
Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0
A-4=B
2+C=B
A+B+C=13

A=b+4
C=B-2
Plug in to equation 3
(B+4)+B+(B-2)=13
Rearrange
B=11/3
A=(11/3)+4= 23/3
C=(11/4)-2= 3/4
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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7B2%7D%20%20%3C%20%20-%203" id="TexFormula1" title=" \frac{y}{2} &lt; - 3"
Allisa [31]
Hey!


Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get y on its own.

<em>Original Equation : </em>
\frac{y}{2} < -3

<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
\frac{2y}{2} < 2 ( -3 )

And we simplify the equation to get our answer.

<em>Old Equation :</em>
\frac{2y}{2} < 2 ( -3 )

<em>New Equation {Changed by Simplification} :</em>
y < -6

<em>So, the equation \frac{y}{2} < -3 simplified is</em>  y < -6.

Hope this helps!


- Lindsey Frazier ♥
8 0
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