During his tennis career in singles play, John won 4 fewer tournament A titles than tournament B titles and 2 more tournament C
titles than tournament B titles. If he won 13 of these titles total, how many times did he win each one?
1 answer:
A-4=B
2+C=B
A+B+C=13
A=b+4
C=B-2
Plug in to equation 3
(B+4)+B+(B-2)=13
Rearrange
B=11/3
A=(11/3)+4= 23/3
C=(11/4)-2= 3/4
You might be interested in
Answer:
293.5
Step-by-step explanation:
40×50/2
=1000 cm²
π×15²
3.14×225
706.5
1000-706.5=293.5 cm²
Let the common multiple be x
3x : 2x
3x = 125
x = 125/3
So, B pays 2x = 2 × 125/3 = £250/3
The answer is 8700. there you go sir or ma'm!
Answer:
the answers are all right
