Joe has a bag of blocks. 3 red blocks and 2 blue blocks weigh 24 ounces while 1 red block and 3 blue blocks weigh 16 ounces. Def
ine your variables and set up a system of equations. DO NOT SOLVE.
1 answer:
Answer: 3r + 2b = 24
r + 3b = 16
Step-by-step explanation:
Let the red blocks be represented by r
Let blue blocks be represented by b
Since 3 red blocks and 2 blue blocks weigh 24 ounces. This will be:
3r + 2b = 24
1 red block and 3 blue blocks weigh 16 ounces. This will be:
r + 3b = 16
Therefore, the equation will be:
3r + 2b = 24
r + 3b = 16
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<span>(4,5); r= square root of 12</span>
Answer:
The correct option is D.
Step-by-step explanation:
The linear regression equation is in the form of

Where,


The formula of r is
![r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n(\sum x^2)-(\sum x)^2][n(\sum y^2)-(\sum y)^2]}}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bn%28%5Csum%20xy%29-%28%5Csum%20x%29%28%5Csum%20y%29%7D%7B%5Csqrt%7B%5Bn%28%5Csum%20x%5E2%29-%28%5Csum%20x%29%5E2%5D%5Bn%28%5Csum%20y%5E2%29-%28%5Csum%20y%29%5E2%5D%7D%7D)
The values are

Using above formula, we get

Therefore option D is correct.
Answer:
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