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n200080 [17]
3 years ago
10

Joe has a bag of blocks. 3 red blocks and 2 blue blocks weigh 24 ounces while 1 red block and 3 blue blocks weigh 16 ounces. Def

ine your variables and set up a system of equations. DO NOT SOLVE.
Mathematics
1 answer:
fredd [130]3 years ago
3 0

Answer: 3r + 2b = 24

r + 3b = 16

Step-by-step explanation:

Let the red blocks be represented by r

Let blue blocks be represented by b

Since 3 red blocks and 2 blue blocks weigh 24 ounces. This will be:

3r + 2b = 24

1 red block and 3 blue blocks weigh 16 ounces. This will be:

r + 3b = 16

Therefore, the equation will be:

3r + 2b = 24

r + 3b = 16

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Can someone pls help??
Vlad1618 [11]

Answer:

a. The y coordinates for A are either 10 or -14

b.  The y coordinates for A are either -11 or 7

Step-by-step explanation:

distance = sqrt ((x2-x1)^2+(y2-y1)^2)

We know Point B and the x coordinate of point A as well as the distance

15 = sqrt ((-4-5)^2+(-2-y1)^2)

15 = sqrt ((-9)^2+(-2-y1)^2)

15 = sqrt (81+(-2-y1)^2)

Square each side

15^2 =sqrt (81+(-2-y1)^2)^2

225 =  81+(-2-y1)^2

Subtract 81 from each side

225-81 = 81-81 +(-2-y1)^2

144 = (-2-y1)^2

Take the square root of each side

±sqrt 144 = sqrt(-2-y1)^2

±12 = (-2-y1)

Add 2 to each side

2±12 = 2-2-y1

2±12 = -y1

14 = -y1  or -10 = -y1

Multiply by -1

-14 = y1  or 10 = y1

The y coordinates for A are either 10 or -14

Now move B to -7,-2

15 = sqrt ((-7-5)^2+(-2-y1)^2)

15 = sqrt ((-12)^2+(-2-y1)^2)

15 = sqrt (144+(-2-y1)^2)

Square each side

15^2 =sqrt (144+(-2-y1)^2)^2

225 =  144+(-2-y1)^2

Subtract 144 from each side

225-144 = 144-144 +(-2-y1)^2

81 = (-2-y1)^2

Take the square root of each side

±sqrt 81 = sqrt(-2-y1)^2

±9 = (-2-y1)

Add 2 to each side

2±9 = 2-2-y1

2±9 = -y1

11 = -y1  or -7 = -y1

Multiply by -1

-11 = y1  or 7 = y1

The y coordinates for A are either -11 or 7

3 0
3 years ago
If m ACB =(11x-32),find the value of x
Digiron [165]

Answer: x= acb/11 + 32/11

Step-by-step explanation:

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

8 0
3 years ago
Solve the following inequality algebraically. -5|1 - 2x| + 6 =< -29​
Blababa [14]

Answer:

x<3

Step-by-step explanation:

-5|1+2x|+6<-29

-5-10x+6<-29

-10x<-30

-----    ----

-10     -10

x<3

8 0
3 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
BigorU [14]
You have two 30-60-90 triangles, ADC and BDC.

The ratio of the lengths of the sides of a 30-60-90 triangle is

short leg : long leg : hypotenuse
     1        :  sqrt(3)  :        2

Using triangle ADC, we can find length AC.
Using triangle BDC, we can find length BC.
Then AB = AC - BC

First, we find length AC.
Look at triangle ACD.
DC is the short leg opposite the 30-deg angle.
DC = 10sqrt(3)
AC = sqrt(3) * 10sqrt(3) = 3 * 10 = 30

Now, we find length BC.
Look at triangle BCD.
For triangle BCD, the long leg is DC and the short leg is BC.
BC = 10sqrt(3)/sqrt(3) = 10

AB = AC - BC = 30 - 10 = 20
6 0
3 years ago
Read 2 more answers
A bakery is selling cookies in two different boxed amounts. A box of 10 cookies costs $4.76, and a box of 25 cookies
soldier1979 [14.2K]

_______________________________

<h3>a) Box of 10: </h3><h3> up = m ÷ ti </h3><h3> = $4.76 ÷ 10 Cookies</h3><h3> = $0.476 ~ $0.48</h3><h3 /><h3> Box of 25: </h3><h3> up = m ÷ ti </h3><h3> = $10 ÷ 25 Cookies</h3><h3> = $0.4</h3><h3 /><h3>b) Box of 10 - Box of 25</h3><h3> = $0.48 - $0.4</h3><h3> = $0.08</h3><h3 /><h3>THE BOX OF 25 COOKIES IS CHEAPER BY $0.08 PER COOKIE.</h3>

_______________________________

3 0
2 years ago
Read 2 more answers
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