Question

The summary statistics for household incomes of all of the houses on Church Street are shown above. Four sample groups were taken from houses on the street. Which sample group has a mean greater than that of the population? *
Group 1



Group 2



Group 3



Group 4

Answer 1

The answer is Group 3 it literally gives the answer to you at the top and I just took the quiz myself.  

Answer 2

Answer:

Group 3

Step-by-step explanation:

The given mean of the population is 55.

For group 1,

Mean = \frac{\sum X}{N}, where X is the all the individual incomes in the group and N is the number of individual incomes in the group.

=$\frac{38+45+76+93+50+54+29+44+62+31}{10}$

=$\frac{522}{10}$

=$52.2$

For group 2,

Mean= $\frac{23+74+50+49+67+34+105+59+40+48}{10}$

=$\frac{549}{10}$

=$54.9$

For group 3,

Mean= $\frac{280+40+39+40+45+52+31+44+50+49}{10}$

=$\frac{670}{10}$

=$67.0$

For group 4,

Mean= $\frac{27+54+42+40+115+48+72+33+28+61}{10}$

=$\frac{520}{10}$

=$52.0$

Since, the mean for group 3 is greater than the given mean, therefore group 3 has the largest mean.