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STatiana [176]
2 years ago
14

A chemistry teacher needs to mix a 20% salt solution with an 80% salt solution to make 20 qt of a 40% salt solution. How many qu

arts of each solution should the teacher mix to get the desired result?
Mathematics
1 answer:
Svetlanka [38]2 years ago
3 0

Answer:

  • 6 2/3 qt 80%
  • 13 1/3 qt 20%

Step-by-step explanation:

It is often convenient to solve a mixture problem by letting a variable represent the quantity of the higher-concentration contributor to the mix.

__

We can let x represent the number of quarts of 80% solution needed. Then (20-x) is the number of quarts of 20% solution needed. The amount of salt in the final mix is ...

  0.80x +0.20(20-x) = 0.40(20)

  0.60x = 0.20(20) . . . . . . . . subtract 0.20(20) and simplify

  x = 20/3 = 6 2/3 . . . . . . . . . divide by 0.60; quarts of 80% solution

  (20 -x) = 13 1/3 . . . . . . . . . . amount of 20% solution needed

The teacher should mix 6 2/3 quarts of 80% solution with 13 1/3 quarts of 20% solution.

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4 0
3 years ago
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2 years ago
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Bogdan [553]
Answer: the median is 6.

Please see the picture attached.

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8 0
3 years ago
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