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Trava [24]
3 years ago
15

During first semester the ratio of the number of students in art class to the number of students in gym class was 2:7. However t

he art classes were really small and the gym classes were large so the principal changed students classes for second semester. In second semester the ratio of the number of students in art class to the number of students in gym class was 5:4. If 75 students were in art class second semester how many were in art class and gym first semester
Mathematics
1 answer:
elena-s [515]3 years ago
4 0
5/4 = 75/g....cross multiply because this is a proportion
5g = 300
g = 300/5
g = 60
so in 2nd semester, there were 75 students in art class and 60 students in gym class....for a total of 135 students.

1st semester....ratio was 2:7...added = 9
art : 2/9(135) = 270/9 = 30 <=== art class had 30
gym: 7/9(135) = 945/9 = 105 <=== gym class had 105

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Step-by-step explanation:

Start by Identifying what you need to keep, in this case that would be X. In order to solve for x, you would need to get rid of any co-efficients. (example: +1.1) To get rid of them, you have to do the opposite action of what it's doing to the equation. (subtraction)

1.1- (-2.1) = 3.2 (if you subtract a negative, it turns positive/ you add) leaving you with x/2 = 3.2.

Now that we have our coefficient out the way, we have to get rid of the division so we can <u>only</u> solve for x. We do that by dividing the remainder of the equation by 2

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8 0
3 years ago
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Butoxors [25]

\boxed{t=11.3h}

<h2>Explanation:</h2><h2></h2>

In this problem we have the following data:

r:speed \\ \\ d:distance \\ \\ t:time \\ \\ \\ r=33.2m/h \\ \\ d=375.16m \\ \\ \\ So \ our \ goal \ is \ to \ find \ t

Speed, time and distance are related with the following formula:

r=\frac{d}{t} \\ \\ \\ Solving \ for \ t: \\ \\ t=\frac{d}{r} \\ \\ t=\frac{375.16}{33.2} \\ \\ \boxed{t=11.3h}

<h2>Learn more:</h2>

Speed: brainly.com/question/14095729

#LearnWithBrainly

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3 years ago
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jeka94
5/3. / 35/6

5/3 * 6/35= 30/105= 6/21= 2/7. The answer to the question is b. 2/7
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