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damaskus [11]
3 years ago
10

!!!!!!!!PLEASE HELP!!!!!!!!

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

Answer:

Step-by-step explanation:

128 divided 2 times X or 128/2 * X

then

128/2 * 5

Volgvan3 years ago
5 0

Answer: the answer is 25

Step-by-step explanation: werewolf

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765434 times 456787654
krek1111 [17]

Answer:3.496408e+14

Step-by-step explanation:

6 0
3 years ago
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What is the 8th term of the geometric sequence 4, −20, 100, …? −312,500 −12,500 62,500 1,562,500?
enot [183]

The first term of GP, a=4

Common ratio=\frac{a2}{a1}=\frac{-20}{4}=-5

r=-5

nth term of GP, an=ar^{n-1}

a8=4*(-5)^{8-1}

a8=4*(-5)^{7}

a8=4*-78125

a8=-312500

4 0
3 years ago
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A store has all board games on sale for 25% off the
Dennis_Churaev [7]

Answer:

$7.20

Step-by-step explanation:

We'll need to find out 40% of 12 then subtract that amount because we're still paying 60% of the original price.

Change the percent to a decimal: 0.4

Multiply the sale price and the decimal

12 · 0.4 = 4.8

Subtract 40% of the price from 12

12 - 4.8 = 7.2

The clearance price of the checker set is $7.20

6 0
3 years ago
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What does k equal in kx+2y=k; if (2,-2)
Aleks [24]
K(2)+2(-2)=k
2k-4=k
+4 +4
2k=k+4
-k -k
K=4
7 0
3 years ago
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Consider the line y= −2/9x-7. Find the equation of the line that is perpendicular to this line and passes through the point , (2
OLEGan [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{2}{9}} x-7\qquad \impliedby \qquad \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so then we can say that

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{-\cfrac{2}{9}} ~\hfill \stackrel{reciprocal}{-\cfrac{9}{2}} ~\hfill \stackrel{negative~reciprocal}{-\left( -\cfrac{9}{2} \right)\implies \cfrac{9}{2}}}

so we're really looking for the equation of a line whos slope is 9/2 and passes through (2 , 3)

(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{9}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{\cfrac{9}{2}}(x-\stackrel{x_1}{2}) \\\\\\ y-3=\cfrac{9}{2}x-9\implies \boxed{y=\cfrac{9}{2}x-6}

now as far as the parallel line

keeping in mind that parallel lines have exactly the same slope, so we're really looking for the equation of a line whose slope is -2/9 and passes through (2 , 3)

(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad \qquad \stackrel{slope}{m}\implies -\cfrac{2}{9} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{-\cfrac{2}{9}}(x-\stackrel{x_1}{2}) \\\\\\ y-3=-\cfrac{2}{9}x+\cfrac{4}{9}\implies y=-\cfrac{2}{9}x+\cfrac{4}{9}+3\implies \boxed{y=-\cfrac{2}{9}x+\cfrac{31}{9}}

6 0
2 years ago
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