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Anon25 [30]
3 years ago
7

Plz help...............................

Mathematics
2 answers:
Natasha2012 [34]3 years ago
8 0
Remember
\frac{x^m}{x^n} =x^{m-n}

so

\frac{a^9}{a^4} =a^{9-4}=a^{5}


first option
kupik [55]3 years ago
7 0
A^5 should be your answer
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–2x + 1 – (–7x + 3) = –4 + 3(x – 2)
natali 33 [55]

Answer:

x = -4

Step-by-step explanation:

–2x + 1 – (–7x + 3) = –4 + 3(x – 2)

-2x + 1 + 7x - 3 = -4 + 3x - 6

-2x + 7x - 3x = -4 - 6 - 1 + 3

2x = -8

x = -8/2

x = -4

8 0
3 years ago
Graph the line with slope -8 and y-intercept 9.
salantis [7]

Answer:

the coordinates will be (0,9) (-8,0) and the equation will be y=(9/8x)+9

Step-by-step explanation:

Im not 100% sure but if im right please mark me as brainliest

8 0
3 years ago
1) 3n-4 = -13<br> Solve &amp; show work
Taya2010 [7]

Answer:

-3

Step-by-step explanation:

3n-4=-13

   +4   +4

3n =-9

3       3

I hope that helped

5 0
3 years ago
Name the component that changes its resistance as the temperature changes.​
babymother [125]

Answer:

Thermistor

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
MATH HELP!!! 100PTS!!!
Lostsunrise [7]

Answer:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Step-by-step explanation:

<u>Given functions</u>:

  p(x)=2x-4

  r(x)=\dfrac{6x-1}{9x+1}

Solve for p(x) = r(x):

\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

<u>Quadratic Formula</u>

x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0

Therefore:

a=18, \quad b=-40, \quad c=-3

Substitute the values of a, b and c into the <u>quadratic formula</u> and solve for x:

\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}

Therefore, the solutions are:

x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0
1 year ago
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