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STALIN [3.7K]
4 years ago
13

Express (x-9)^2 as trinomial in standard form

Mathematics
2 answers:
liq [111]4 years ago
7 0
= (x - 9)(x - 9)
= x(x - 9) - 9(x - 9)
= x^2 - 9x - 9x + 81
= x^2 - 18x + 81  Answer
Ray Of Light [21]4 years ago
5 0

{x}^{2}  - 18x + 81
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Please help me with this one.
Alecsey [184]

Your answer would be C.

    If you substitute 14 for X and add it to 9. You would get 23

7 0
4 years ago
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The following data values represent a population what is the variance of the values 17, 5 ,11, 1,11
marin [14]
1) from smaller to higher:
1,5,11,11,17

2) find the mean
<span>1 + 5 + 11 + 11 + 17 = </span><span>45
</span>mean = 45/5 = 9

Variance = Σ(x- mean)²/(N-1)
[(1-9)² + (5-9)²+(11-9)² + (11-9)²+ (17-9)² ]'(5-1) =  38

Variance = 38

6 0
4 years ago
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I need help on how to solve this and what the answer is
stiks02 [169]
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so 4/3 x pi x 64
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3 0
3 years ago
Oleg, Sasha, and Dima share 600 toys. Sasha has twice as many toys as Oleg. Dima has 40 more toys than Oleg. How many toys does
Anika [276]

Answer: 140

Oleg, Sasha, and Dima shared 600 toys. Sasha had twice as many toys as Oleg. Dima had 40 more toys than Oleg.

Let the number of toys Oleg has = x

Let the number of toys Sasha has = y

Let the number of toys Dima has = z

Sasha had twice as many toys as Oleg

So y = 2*x= 2x

Dima had 40 more toys than Oleg.

z = x + 40

Oleg, Sasha, and Dima shared 600 toys

x + y + z= 600

We know y=2x and z=x+40

Replace it for y and z

Subtract 40 on both sides

Divide by 4 on both sides

Oleg had 140 toys

Step-by-step explanation:

6 0
4 years ago
Calculate the angles of a parallelogram if the sum of the three angles is 310°
Gennadij [26K]

9514 1404 393

Answer:

  adjacent angles are 50° and 130°

Step-by-step explanation:

The sum of all 4 angles in a parallelogram is 360°, so the fourth angle must be ...

  360° -310° = 50°

Adjacent angles are supplementary, so the other two angles must be ...

  180° -50° = 130°

The angles in the parallelogram are either 50° or 130°. Adjacent angles are different.

8 0
3 years ago
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