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Anni [7]
3 years ago
5

HELP ASAP IF YOU TAKE THE POINTS IM REPORTING U QUESTION IN PIC

Mathematics
2 answers:
Andrew [12]3 years ago
7 0
Let's call the number x. So four times the number minus five would look like
4x-5
Twice the number plus three would look like
2x+3
Now make the two equations equal
4x-5=2x+3
I'm going to subtract 2x from each side
2x-5=3
Now I'm going to add five to each side
2x=8
Now divide both sides by 2
x=4
To double check, just plug back into the original equations
4(4)-5=11
2(4)+3=11
They are equal, so the answer is x=4.
Airida [17]3 years ago
4 0

Step-by-step explanation:

Let the number be x,

Then, according to the question,

4x-5=2x+3

(we need to find the value of x)

4x-2x=5+3

= 2x=8

= x=8/2

= x=4

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Answer: lenght is 50yrds, width is 30yrds

Step-by-step explanation:

Perimeter of a pool = 2( lenght x breadth)

Perimeter = 160yrds

If the lenght is 10yrds less than twice the width then,

lenght = 2w - 10,

Where w is the width

Then from p = 2(L + w)

160 = 2( 2w - 10 + w)

160 = 2(3w - 10)

160 = 6w - 20

160 + 20 = 6w = 180

width w = 180/6 = 30yrds

From p = 2(L + w)

160 = 2(L + 30)

160 = 2L + 60

160 - 60 = 2L = 100

L = 100/2 = 50yrds

3 0
3 years ago
determine the quadratic function of f whose graph is given. The vertex is (1,-3) and the y-intercept is -2
LuckyWell [14K]
Hmmm the y-intercept is at -2?  what does that mean?  well, is where the graph "intercepts" or touches the y-axis, and when that happens, x = 0, so the point is really ( 0 , -2 ).

and we know where the vertex is at.  Let's assume a vertical parabola, in which case the squared variable is the "x".

\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
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\\\\\\
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3 years ago
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Shtirlitz [24]
The answer will be B.exponential 
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3 years ago
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olganol [36]

Answer:

125

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1 part = 75

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3 0
3 years ago
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Answer:

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3 0
3 years ago
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