In the given expression 6X² + 13X +6, we can easily identify the values of a, b and c. These values are a=6, b=13 and c=6
For the value of "ac", we have:
ac=6*6
ac=36
For a sum of b are 4, we have
ac+b=36+13=49
Therefore, the answer for the last question "The two numbers that have a product of ac and a sum of b are 4 and 9".
You can set both equations together
y = -3x + 1
and y = x - 3
we can replace the y of one equation with the other side
-3x+1 = x-3
add 3x on both sides
1 = x + 3x -3
add 3 on both sides
1 + 3 = x+ 3x
simplify
4 = 4x
divide by 4 on both sides
x = 1
y = x - 3
y = 1 - 3
y = 2
So the solution is: (1,2)
Answer:
b ≈ 7.54 cm
Step-by-step explanation:
Pythagorean Theorem
a² + b² = c²
a and b are the sides and c is the hypotenuse
hypotenuse is 11 cm
a side is 8 cm
so
8² + b² = 11²
64 + b² = 121
-64 -64
b² = 57
√b² = √57
b ≈ 7.54 cm ( use ≈ because its rounded so its not exact)
Answer:


Step-by-step explanation:
Given



Required
Find P(A) and P(B)
We have that:
--- (1)
and
--- (2)
The equations become:
--- (1)

Collect like terms


Make P(A) the subject

--- (2)


Substitute: 
![[0.770 - P(B)] * P(B) = 0.144](https://tex.z-dn.net/?f=%5B0.770%20-%20P%28B%29%5D%20%2A%20P%28B%29%20%3D%200.144)
Open bracket

Represent P(B) with x

Rewrite as:

Expand

Factorize:
![x[x - 0.45] - 0.32[x - 0.45]= 0](https://tex.z-dn.net/?f=x%5Bx%20-%200.45%5D%20-%200.32%5Bx%20-%200.45%5D%3D%200)
Factor out x - 0.45
![[x - 0.32][x - 0.45]= 0](https://tex.z-dn.net/?f=%5Bx%20-%200.32%5D%5Bx%20-%200.45%5D%3D%200)
Split

Solve for x

Recall that:

So, we have:

Recall that:

So, we have:


Since:

Then:



We have that

, which means

reduces to

when

, or reduces to

when

.
So we can expand the summation as

Notice that the 10 contributes a total of 30 from the first sum, and -30 from the second sum, so those terms cancel, leaving us with