All categories

3 years ago

Percent of change markup discount

Mathematics

2 answers:

igomit [66]3 years ago

7 0

I really have no clue with you best of luck finding the answer sorry I couldn’t help

vichka [17]3 years ago

4 0

You calculate the markup or markdown in absolute terms (you find by how much the quantity changed), and then you calculate the percent change relative to the original value. So they're really just another form of "increase - decrease" exercises.

Example:

A computer software retailer used a markup rate of 40%. Find the selling price of a computer game that cost the retailer $25.
The markup is 40% of the $25 cost, so the markup is:

(0.40)(25) = 10
Then the selling price, being the cost plus markup, is:

25 + 10 = 35

The item sold for $35.

You might be interested in

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

3 years ago

Teague is participating in a 50K run to raise money for a charity. He has already raised $102 and will receive $1.40 for each ki

Volgvan

He has to run 45 kilometers

3 0

3 years ago

(1) Cos AcosecA=cot A

Mashutka [201]

Answer:

The Basic Identities are :

$cosec(A) = \frac{1}{ \sin(A) }$

$\tan(A) = \frac{ \sin(A) }{ \cos(A) }$

$\cot(A) = \frac{1}{ \tan(A) } = \frac{ \cos(A) }{ \sin(A) }$

So for this question :

$\cos(A)cosec(A) = \cot(A)$

$l.s.h = \cos(A) \times \frac{1}{ \sin(A) }$

$l.s.h = \frac{ \cos(A) }{ \sin(A) }$

$l.sh = \cot(A) \: (proven)$

7 0

3 years ago

Whats 1+1+1+1+1+1+1+1x0+1+1+1+1x1=?

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

You buy two packages of almonds. One package is 10.47 kg and the other is 8.23 kg. What is the difference?

fomenos

Answer:

2.04 kg

Step-by-step explanation:

5 0

3 years ago