What is mL BCD ? THANK U <3

HELP ASAP ILL GIVE U BRAINLIEST AND A THANKS

Olenka [21]

Answer:

you have to write it down on a piece of paper and go from there

Step-by-step explanation:

5 0

2 years ago

What is 3+4x+2+2x+2x

Sonja [21]

Answer:

8x + 5

Step-by-step explanation:

3 + 4x + 2 + 2x + 2x

3 + 2 = 5

4x + 2x = 6x

6x + 2x = 8x

5 0

2 years ago

What sample size is needed to give a margin of error within in estimating a population mean with 95% confidence, assuming a prev

atroni [7]

Answer:

$n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion $\pi$ (if no previous estimate use 0.5) and M is the desired margin of error.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a p-value of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Needed sample size:

The needed sample size is n. We have that:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 1.96\sqrt{\frac{\pi(1-\pi)}{n}}$

$\sqrt{n}M = 1.96\sqrt{\pi(1-\pi)}$

$\sqrt{n} = \frac{1.96\sqrt{\pi(1-\pi)}}{M}$

$(\sqrt{n})^2 = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

$n = (\frac{1.96\sqrt{\pi(1-\pi)}}{M})^2$

The sample size needed is n(if a decimal number, round up to the next integer), considering the estimate of the proportion $\pi$ (if no previous estimate use 0.5) and M is the desired margin of error.

4 0

2 years ago

A central angle of a circle that measures 2 radians intercepts an arc of length 10 cm. What is the length of the radius?

Ilya [14]

Answer:

5 cm

Step-by-step explanation:

Arc length (S) = 10 cm

Central angle $(\theta)$ = 2 radians