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serg [7]
3 years ago
10

Whats 7x6-6x11-66+55?

Mathematics
1 answer:
GenaCL600 [577]3 years ago
3 0

the answer is -35 hope this helped

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Please help I am not soo good at math
hram777 [196]

Answer:

D

Step-by-step explanation:

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2 years ago
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Decide whether the following statement is true or false. If the degree of the numerator of a rational function equals the degree
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B. The statement is true because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has a horizontal asymptote that is equal to the ratio of the leading coefficients.

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3 years ago
Barrett works at an ice cream shop. The function f(x) represents the amount of money Barrett earns per gallon of ice cream, wher
Sliva [168]

The value of f(g(x)) is 6x^{3} +4

Explanation:

The function f(x) is given by

f(x)=2x^{2} +4

The function g(x) is given by

g(x)=\sqrt{3x^{3} }

To determine the value of f(g(x)), let us first substitute the value of g(x).

Thus, we get,

f(g(x))=f(\sqrt{3x^{3} } )

Now, substituting for x=\sqrt{3x^{3} } in the function f(x), we get,

f(g(x))=2(\sqrt{3x^{3} } )^2+4

Simplifying, the expression, we get,

f(g(x))=2({3x^{3} } )+4

Multiplying the term within the bracket, we have,

f(g(x))=6x^{3} +4

Thus, the value of f(g(x)) is 6x^{3} +4

Hence, the value of f(g(x)) represents the total amount of money that Barrett earns for working x hours.

4 0
3 years ago
Gloria and her 3 friends will share a pizza equally.
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I believe its b :)))
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Answer:

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Step-by-step explanation:

Remember that a function has its critical points where the derivative equal zero. Therefore we need to compute the derivative of this function and find the points where the derivative is zero. Using the chain rule and the product rule we get that

f'(x)=  -e^{-4x}(11+4x)

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Now, if the second derivative evaluated at that point is less than 0 then the point is a maximum and if is greater than zero the point is a minimum.

Since

f''(x) = 8e^{-4x} (5+2x)\\f''(-11/4) = -239496.56

x= -11/4 is a maximum.

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3 years ago
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