Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain...(I'm including the range..)
Domain:(-∞,∞),{x║x ∈ R}
Range:(-8,∞),{y║y≥-8}
Answer:
=4x^2−12x+9
Step-by-step explanation:
=(2x+−3)(2x+−3)
=(2x)(2x)+(2x)(−3)+(−3)(2x)+(−3)(−3)
=4x2−6x−6x+9
=4x2−12x+9
Answer:
<u>Q/ Draw a line ; Ans; </u>

*explain ; We put the 5 in the denominator and 5 multiply 1 + 4 so equal 9 so the choice 9/5 .
Ans; 7/3—> 2 1/3
*explain ; We put the 3 in the denominator and 3 multiply 2 + 1 so equal 7 so the choice 7/3 .
Ans; 12/10 —> 1 1/5
*explain; simple (12 and 10) ÷ 2 so equal 6/5
We put the 5 in the denominator and 5 multiply 1 + 1 so equal 6 so the choice 6/5 =12/10 .

<u>Q/ Compare the fractions;Ans;</u>

* explain; 2/3 = 0.66 and 14/6=2.33 so 2.33 greater from 0.66 so 14/6 greater from 2/3 .

* explain; 3/8 = 0.375 and 8/3=2.666 so 2.666 greater from 0.375 so 8/3 greater from 3/8 .

* explain; 2 1/6 —> We put the 6 in the denominator and 6 multiply 2 + 1 so equal 13 so equal 13/6
13/6 = 2.16 and 5/9=0.55 so 2.16 greater from 0.55 so 13/6 = 2 1/6 greater from 5/9 .
<u>Q/Add; Ans;</u>


<u>Q/Subtract; Ans;</u>


<u>Q/ Multiply;Ans;</u>


<u>Q/Divide;Ans;</u>


I hope I helped you^_^
First find slope or rate of winston(0,-100) and (3,-16)
slope=(y2-y1)/(x2-x1)
slope=(-16-(-100))/(3-0)=(-16+100)/(3)=84/3=28/1
wane slope or elevation gain
y=mx+b
m=slope or rate of elevaion gain
b=yintercept or starting oint
y=30x-105
slope or rate of change is 30
30 vs 28
wane acends faster than winston
also, the starting point or when x=0 point is the starting point
wane: -105 is start
winston: -100 is start
wane started deeper
so the true statements are
Wayne ascends at a faster speeds
Wayne was deeper when he began ascending
X^2 - y^2 = a
2xy = b
x^2 + y^2 = c
A polynomial identity is an equation that is always true.`1
You can relate x^2 + y^2 with x^2 - y^2 and 2xy in this ways.
1) Step 1:
[x^2 + y^2]^2 = x^4 + 2(xy)^2 + y^4 = c^2
2) Step 2:
[x^2 - y^2] = x^4 - 2(xy)^2 + y^2 = a^2
(2xy)^2 = 4(xy)^2 = b^2
x^4 - 2(xy)^2 + y^2 + (2xy)^2 = x^4 + 2(xy)^2 + y^2
------------------------ ---------- --------------------------
↓ ↓ ↓
a^2 b^2 = c^2
Answer: the identity is
c^2 = a^2 + b^2 equivalent to
(x^2 + y^2)^2 = (x^2 - y^2)^2 + (2xy)^2