Answer:
60 feet
Step-by-step explanation:
The height, h (in meters), of the object launched from a platform is represented by the equation
where x is the time (in seconds) passed after the launch.
The time of launch is 
(0 seconds passed after the launch)
Substitute to find the height:
Answer:
hour and a half
Step-by-step explanation:
Answer:
thx
Step-by-step explanation:
Answer:
b
Step-by-step explanation:
because if you look at it the x-coordinate is -6 and the y-coordinate is positive 4
In the standard form of the equation
![\\ \ f(t)=Acos[b(t\pm c)]+k\\ \\](https://tex.z-dn.net/?f=%20%5C%5C%20%5C%20f%28t%29%3DAcos%5Bb%28t%5Cpm%20c%29%5D%2Bk%5C%5C%20%5C%5C%20)
The middle line =k
For our given problem
f(t) = 40cos (80t + 20)
On comparison we get k=0
Hence middle line=0
