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mariarad [96]
3 years ago
12

A family drives for 3 hours at an average rate of 57 miles per hour how far does the family travel

Mathematics
2 answers:
horrorfan [7]3 years ago
5 0

Answer:

171 miles

Step-by-step explanation:

<h2><u>Finding the distance</u></h2><h3><u>make use of the distance formula:</u></h3>

distance = speed * time

in this case the speed is  57 miles per hour

the time is 3 hours

hence distance = 57 * 3

<u><em>= 171 miles</em></u>

Alex777 [14]3 years ago
3 0

Answer:

171 miles

Step-by-step explanation:

57 x 3 = 171

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Answer:

7π

Step-by-step explanation:

SO first find the area of the whole circle

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a=πr^2

So 3^2=9

9π

Now the two circles which are the same in area due to having the same radius

so if you plug in the 1 for radius the answer would just be π or 1π

now multiply that by 2 becuase there are 2 identical circles

π*2=2π

Now subtract

9π-2π=7π

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How to determine the maximum and minimum lengths of a missing side on a triangle?
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Well to find the missing side you're going to need the other two. Take the one side and multiply by itself. Take the other one and multiply by itself. Add those two products. Then root it. Basically find something that multiplys by itself to get that product
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3 years ago
The table below shows all outcomes for rolling 2 dice. The bold numbers 1 through 6 show the possible results for each die. All
Leokris [45]

Part I:

1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.

2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.

Part II:

Here you can see 36 possible outcomes.

1. The probability that at least 1 die is a 4 is:

Pr(A)=\dfrac{11}{36} - (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).

2. The probability that the sum of the dice is greater than 5 is:

Pr(B)=\dfrac{26}{36}=\dfrac{13}{18}.

3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is

Pr(A\cap B)=\dfrac{9}{36}=\dfrac{1}{4}.

4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:

Pr(A\cup B)=\dfrac{28}{36}=\dfrac{7}{9}.

4 0
3 years ago
PLEASE HELP
dsp73

Answer:

All events are independent

Step-by-step explanation:

You are given the table

\begin{array}{cccc}&\text{Chocolate}&\text{Vanilla}&\text{Total}\\\text{Adults}&0.21&0.39&0.60\\\text{Children}&0.14&0.26&0.40\\\text{Total}&0.35&0.65&1.00\end{array}

Two events A and B are independent when

Pr(A\cap B)=Pr(A)\cdot Pr(B)

a) A="Chocolate"

B="Adults"

A and B="Chocolate and Adults"

Pr(A)=0.35\\ \\Pr(B)=0.60\\ \\Pr(A\cap B)=0.21

Since 0.35\cdot 0.60=0.21 events are independent

b) A="Children"

B="Chocolate"

A and B="Children and Chocolate"

Pr(A)=0.40\\ \\Pr(B)=0.35\\ \\Pr(A\cap B)=0.14

Since 0.40\cdot 0.35=0.14 events are independent

c) A="Vanilla"

B="Children"

A and B="Vanilla and Children"

Pr(A)=0.65\\ \\Pr(B)=0.40\\ \\Pr(A\cap B)=0.26

Since 0.65\cdot 0.40=0.26 events are independent

4 0
3 years ago
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