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4vir4ik [10]
3 years ago
10

What is the change that occurs to the parent function f(x) = x^2 given the function f(x) = (x + 1)^2 - 5.

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0
The translation is down 5 because if you simplify or solve the second f(x), it would be x^2 - 5. I hope this helps :)
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-34x+6=-28<br> I need to learn how to solve for x
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Answer:

x=1

Step-by-step explanation:

-34x+6=-28

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-34x=-34

-34     -34

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Subtract 6 from both sides. on the left the 6 will be canceled out and on the right -28-6= -34

Than you divide -34 on both sides on the left the -34 will be canceled and on the right -34 divided bt-34 is positive 1. So x equals 1.

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A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

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