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Colt1911 [192]
4 years ago
8

Which distribution has the greatest spread

Mathematics
2 answers:
professor190 [17]4 years ago
8 0
Calculate the range of each option; 

A) 13.7-3.1=10.6
B) "= 422.3 
C) "=31.2
D) 225.9 

As noticed, Option B has the widest range, therefore, wider spread of data. 

Hope I helped :) 
Verizon [17]4 years ago
8 0

le answer is b and i need more characters to post this answer

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WILL MARK BRAINLEIST
lina2011 [118]

Answer:

decrease by 50%

Step-by-step explanation:

\frac{0.4x}{0.8y} =\frac{x}{2y}      

Decreased by 60% = (100%-60%)x = 0.4x.

Decreased by 20% = (100%-20%)x = 0.8x.

\frac{x}{y} initial fraction, and we can see that denominator will increase 2 times, so fraction will decrease 2 times, or decrease by 50%.

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Read 2 more answers
If a polynomial function f(x) has roots -8, 1, and 6i, what must also be a root of f(x)?
Naddik [55]

Answer:

it must also have the root : - 6i

Step-by-step explanation:

If a polynomial is expressed with real coefficients (which must be the case if it is a function f(x) in the Real coordinate system), then if it has a complex root "a+bi", it must also have for root the conjugate of that complex root.

This is because in order to render a polynomial with Real coefficients, the binomial factor  (x - (a+bi)) originated using the complex root would be able to eliminate the imaginary unit, only when multiplied by the binomial factor generated by its conjugate: (x - (a-bi)). This is shown below:

(x-(a+bi))*(x-(a-bi))=\\(x-a-bi)*(x-a+bi)=\\([x-a]-bi)*([x-a]+bi)=\\(x-a)^2-(bi)^2=\\(x-a)^2-b^2(-1)=\\(x-a)^2+b^2

where the imaginary unit has disappeared, making the expression real.

So in our case, a+bi is -6i (real part a=0, and imaginary part b=-6)

Then, the conjugate of this root would be: +6i, giving us the other complex root that also may be present in the real polynomial we are dealing with.

5 0
3 years ago
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