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Llana [10]
3 years ago
10

PLEASE HELP ASAP!!!!!!!!!!

Mathematics
2 answers:
Andre45 [30]3 years ago
5 0
I think the answer is c
harina [27]3 years ago
5 0
\dfrac{1}{2^{-2}x^{-3}y^5}=\dfrac{2^2x^3}{y^5}\\\\\\
\dfrac{2^2\cdot2^3}{(-4)^5}=\dfrac{2^5}{(-4)^5}=\left(\dfrac{2}{-4}\right)^5=\left(-\dfrac{1}{2}\right)^5=\boxed{-\dfrac{1}{32}}

Answer A)
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