Question

PLEASE HELP ASAP!!!!!!!!!!

Answer 1

I think the answer is c

Answer 2

$\dfrac{1}{2^{-2}x^{-3}y^5}=\dfrac{2^2x^3}{y^5}\\\\\\ \dfrac{2^2\cdot2^3}{(-4)^5}=\dfrac{2^5}{(-4)^5}=\left(\dfrac{2}{-4}\right)^5=\left(-\dfrac{1}{2}\right)^5=\boxed{-\dfrac{1}{32}}$

Answer A)