Answer:
How many grams Iron(II) Sulfide in 1 mol? The answer is 87.91. We assume you are converting between grams Iron(II) Sulfide and mole. You can view more details on each measurement unit: molecular weight of Iron(II) Sulfide or mol The molecular formula for Iron(II) Sulfide is FeS. The SI base unit for amount of substance is the mole.
Explanation:
F = M x A
F = 0.25 x 196
F = 49 N
Answer:
A. Potassium phosphate: K3PO4
B. Copper (II) sulfate: CuSO4
C. Calcium chloride: CaCl2
D. Titanium dioxide: TiO2
E. Ammonium nitrate: NH4NO3
F. Sodium bisulfate: NaHSO4
Explanation:
All are ionic salts with different valent (mono valent cation or poly valent cation and anions) ions.
Answer:

Explanation:
To find the weight (W) of the pond contents first we need to use the following equation:
(1)
Where m the mass and g is the gravity
Also, we have that the mass is:
(2)
Where ρ is the density and V the volume
We cand calculate the volume as follows:
(3)
Where L is the length, w is the wide and d is the depth
By entering equation (2) and (3) into (1) we have:

Therefore, the weight of the pond is 6.65x10⁶ lbf.
I hope it helps you!