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bonufazy [111]
4 years ago
6

Derek needs a tool that delivers 5.00 mL of a sodium hydroxide solution.which tool would be best for him to use

Chemistry
2 answers:
Delvig [45]4 years ago
7 0
Because 5.00 mL is a small amount, the best tool he could use is a pipette. 

Pipette or sometimes spelled as pipet can be used to transport liquid samples. It is made out of glass or plastic and can is usually used to transfer measured volumes of liquid from one container to another. Before the pipette was invented, scientists used to use straws and they would suck in the samples carefully. 
natta225 [31]4 years ago
7 0

Answer:

b. pipette

Explanation:

:p

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How many grams of oxygen will react with 2.0 grams of iron II sulfide?
Elenna [48]

Answer:

How many grams Iron(II) Sulfide in 1 mol? The answer is 87.91. We assume you are converting between grams Iron(II) Sulfide and mole. You can view more details on each measurement unit: molecular weight of Iron(II) Sulfide or mol The molecular formula for Iron(II) Sulfide is FeS. The SI base unit for amount of substance is the mole.

Explanation:

3 0
3 years ago
What force is needed to give a 0.25-kg arrow acceleration of 196m/s^2?<br><br>please help!!
lana [24]
F = M x A
F = 0.25 x 196
F = 49 N
7 0
4 years ago
The following ionic compounds are found in common household products. write the formulas for each compound:
victus00 [196]

Answer:

A. Potassium phosphate: K3PO4

B. Copper (II) sulfate: CuSO4

C. Calcium chloride: CaCl2

D. Titanium dioxide: TiO2

E. Ammonium nitrate: NH4NO3

F. Sodium bisulfate: NaHSO4

Explanation:

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3 0
3 years ago
The coyote is found across North America which makes it a specialist species.
Bingel [31]

Answer:   false

Explanation:

8 0
3 years ago
A waste treatment pond is 50 m long and 25 m wide, and has an average depth of 2 m. The density of the waste is 75.3lbm/ft^3 .Ca
umka21 [38]

Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

6 0
4 years ago
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