There are a lot of empty space between the particles
Answer: 16.32 g of
as excess reagent are left.
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of
require = 1 mole of
Thus 0.34 moles of
will require=
of
Thus
is the limiting reagent as it limits the formation of product and
is the excess reagent.
Moles of
left = (0.68-0.17) mol = 0.51 mol
Mass of
Thus 16.32 g of
as excess reagent are left.
Answer:
color
Explanation:
Scientists can use the color of minerals to tell them apart.
Answer:
THE MOLARITY OF SODIUM CHLORIDE IN THE CONTAINER IS 0.3846 M.
Explanation:
Molarity of a solution is the number of moles of solute per dm3 of solution.
Mass concentration = Molar concentration * Molar mass
1. calculate the mass concentration;
Mass conc. = 45 g in 2 L
= 45 g in 2 dm3
In 1 dm3, the mass will be 45 / 2
= 22.5 g/dm3 of NaCl.
2. Calculate the molar mass;
(Na = 23, Cl = 35.5)
Molar mass = ( 23 + 35.5 ) g/mol
Molar mass = 58.5 g/mol
3. calculate the molarity
Molarity = mss concentration / molar mass
Molarity = 22.5 g/dm3 / 58.5 g/mol
Molarity = 0.3846 mol/dm3 of NaCl.
The molarity of sodium chloride in the container is 0.3846 mol/dm3