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emmasim [6.3K]
3 years ago
14

A pure sample contains only nitrogen and oxygen atoms. If the sample is 30.4% nitrogen, by weight, what is the empirical formula

of the molecule? 1. N2O3 2. NO2 3. N2O 4. N2O5 5. NO
Chemistry
1 answer:
andrew-mc [135]3 years ago
8 0

Answer: 2. NO_2

Explanation:

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of N = 30.4 g

Mass of O= 69.6 g

Step 1 : convert given masses into moles

Moles of N=\frac{\text{ given mass of N}}{\text{ molar mass of N}}= \frac{30.4g}{14g/mole}=2.2moles

Moles of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{69.6g}{16g/mole}=4.4moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For N = \frac{2.2}{2.2}=1

For O =\frac{4.4}{2.2}=2

The ratio of N: O = 1; 2

Hence the empirical formula is NO_2

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Answer:

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3 years ago
Is 2 KNO₃ + H₂CO₃ → K₂CO₃ + 4 HNO₃ a balanced equation
krok68 [10]

Hey there!

The elements in this equation are K, N, O, H, and C.

Let's count how many of each are on each side to see if it is balanced.

K: 2 on the left, 2 on the right.

<em>N: 2 on the left, 4 on the right. </em>

<em>O: 9 on the left, 6 on the right. </em>

<em>H: 2 on the left, 4 on the right. </em>

C: 1 on the left, 1 on the right.

Notice that there are different amounts of N, O, and H on the left side and the right side.

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6 0
3 years ago
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PIT_PIT [208]

Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.

<span>
Moles of HCl = 5.5 g HCl ( 1 mol HCl / 36.46 g HCl ) = 0.1509 mol HCl</span>

<span>
Molality = 0.1509 mol HCl / 200 g C2H6O ( 1 kg / 1000 g )
Molality = 0.7543 mol / kg</span>


<span>The concentration in molality of hcl in a solution that is prepared by dissolving 5.5 g of hcl in 200.0 g of c2h6o is 0.7453 molal.</span>
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3 years ago
Perform the following
docker41 [41]

Answer:

8.73

Explanation:

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also it is to 2 sigfigs because we know that we go by the least number of sigfigs. hope this helped!

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