If a=2, b-3 and c=5. Thr value of 4a-2b+5c are

Micheal buys two bags or chips and three boxes of pretzels for $5.13 . He then buys another bag of chips and 2 boxes of pretzels

trapecia [35]

Answer:

So a bag of chip costs $2.39

Step-by-step explanation:

Let x = cost of a bag of chip

Let y = cost of a box of pretzel

Micheal buys two bags of chips and three boxes of pretzels for $5.13

This means

2x + 3y = 5.13 - - - - - - - - - -1

He then buys another bag of chips and 2 boxes of pretzels for $3.09

This means

x + 2y = 3.09 - - - - - - - - - - - -2

Solving equation 1 and equation 2 simultaneously and using the elimination method,

Multiply equation 1 by 1 and equation 2 by 2

2x + 3y = 5.13

2x + 6y = 6.18

Subtracting,

-3y = -1.05

y = -1.05/-3= $0.35

Put y= 0.35 in equation, x + 2y = 3.09

x + 2(0.35)= 3.09

x + 0.7= 3.09

x = 3.09-0.7 = $ 2.39

So a bag of chip costs $2.39

5 0

3 years ago

I need help fast please answer!

frez [133]

Answer:

B

Step-by-step explanation:

3 0

3 years ago

Michelle tried to solve an equation step by step. \begin{aligned} t-\dfrac35&=\dfrac45\\\\ t-\dfrac35+\dfrac35&=\dfrac45

valentinak56 [21]

Answer:

Step 2

Step-by-step explanation:

Michelle's step in trying to solve the equation is given below:

$\begin{aligned} t-\dfrac35&=\dfrac45\\\\ t-\dfrac35+\dfrac35&=\dfrac45+\dfrac35&\green{\text{Step } 1}\\\\ t&=1&\blue{\text{Step } 2} \end{aligned}$

Michelle made a mistake in Step 2.

The right hand side of Step 1: $\dfrac45+\dfrac35\neq 1$

Rather, the correct sum is:

$\dfrac45+\dfrac35=\dfrac75\\\\=1\dfrac25$

5 0

3 years ago

What is the answer explain please

eduard

Answer:

Pattern B

<h3> Explain: </h3>

A quadratic relationship is characterized by constant second differences.

Pattern A 

Sequence: 0, 2, 4, 6

First Differences: 2, 2, 2 . . . . constant indicates a 1st-degree (linear, arithmetic) sequence

__________________________________________________________

Pattern B

Sequence: 1, 2, 5, 10

First Differences: 1, 3, 5

Second Differences: 2, 2 . . . . constant indicates a 2nd-degree (quadratic) sequence

__________________________________________________________

Pattern C

Sequence: 1, 3, 9, 27

First Differences: 2, 6, 18

Second Differences: 4, 12 . . . . each set of differences has a common ratio, indicating an exponential (geometric) sequence

__________________________________________________________

Pattern B shows a geometric relationship between step number and dot count.

6 0

2 years ago

A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is

Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

$M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}$

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k" (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

$M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N} = \frac{(x_1 + x_2 + ... + x_n)}{N} = M$

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

$SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }$

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0

2 years ago