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Marrrta [24]
3 years ago
6

Out of 40 students In a class7 20% were absent how many students were present​

Mathematics
2 answers:
DerKrebs [107]3 years ago
7 0

Answer:

8 were absent

Step-by-step explanation:

20% of 40 is 8

Monica [59]3 years ago
5 0

Answer:

32 students were present

Step-by-step explanation:

total students =40

absent percent=20%

present percent= 100-20

=80%

total present student =80%of 40=32

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How many integers between 14 and 3,452 can be divided by 42 with a remainder of zero?
soldi70 [24.7K]
      _______
42 I 3,452

82 with a remainder

There are <u>82</u> integers between 14 and 2452 that can be divided with a remainder of 0
4 0
3 years ago
What is the distance between the building B (4, 6) and the station K (–6, –2)? Use a calculator to round to the nearest tenth.
Svetllana [295]

Answer:

The answer is

<h2>12.8 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

d =  \sqrt{ ({x1 - x2})^{2} +  ({y1 - y2})^{2}  }  \\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

B (4, 6) and K (–6, –2)

The distance is

|BK|  =  \sqrt{ ({4 + 6})^{2}  +  ({6 + 2})^{2} }  \\  =  \sqrt{ {10}^{2} +  {8}^{2}  }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  =  \sqrt{100 + 64}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  =  \sqrt{164}  \\  = 2 \sqrt{41}  \\  = 12.80

We have the final answer as

<h3>12.8 to the nearest tenth</h3>

Hope this helps you

5 0
3 years ago
8 1/2 - 6 1/4 please subtract
Alexandra [31]

Answer:

2.25

Step-by-step explanation:

8.5-6.25

(8-6)+(0.5-0.25)

2+0.25

2.25

4 0
2 years ago
Read 2 more answers
37.5% 1/3 25% and 3/10 least to greatest
barxatty [35]
25% 3/10 1/3 and 37.5%

.25,.30,.33,.375
7 0
3 years ago
The number of texts per day by students in a class is normally distributed with a 
kobusy [5.1K]

Answer:

1, 2, 6

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation

Given that mean (μ) = 130 texts, standard deviation (σ) = 20 texts

1) For x < 90:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{90-130}{20} =-2

From the normal distribution table, P(x < 90) = P(z < -2) = 0.0228 = 2.28%

Option 1 is correct

2) For x > 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

From the normal distribution table, P(x > 130) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 50%

Option 2 is correct

3) For x > 190:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{190-130}{20} =3

From the normal distribution table, P(x > 3) = P(z > 3) = 1 - P(z < 3) = 1 - 0.9987 = 0.0013 = 0.13%

Option 3 is incorrect

4)  For x < 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

For x > 100:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{100-130}{20} =-1.5

From the normal table, P(100 < x < 130) = P(-1.5 < z < 0) = P(z < 0) - P(z < 1.5) = 0.5 - 0.0668 = 0.9332 = 93.32%

Option 4 is incorrect

5)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{130-130}{20} =0

Option 5 is incorrect

6)  For x = 130:

z=\frac{x-\mu}{\sigma} \\\\z=\frac{160-130}{20} =1.5

Since 1.5 is between 1 and 2, option 6 is correct

5 0
2 years ago
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