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jolli1 [7]
3 years ago
11

The number of timeshare condos available at sunset beach is 3/5 the number of timeshare condos available at playa del mar. if th

e total number of timeshare condos available at the two beaches combined is 240, what is the difference between the number of condos available at sunset beach and the number of condos available at playa del mar?
Mathematics
1 answer:
natita [175]3 years ago
5 0
60 condos in the difference
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What are the common factors of 15,45 and 90
Nookie1986 [14]
List all the factors.

Factors of 15: 1, 3, 5, 15
Factors of 45: 1, 3, 5, 9, 15, 45
Factors of 90: 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90

The common factors of 15, 45, and 90 are 1, 3, 5, and 15.
3 0
3 years ago
Suppose a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 h
vladimir2022 [97]

A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.

C) The probability the golfer got six holes-in-one during a single game is close to 0%.

<h2 /><h2><u>How to determine probabilities</u></h2>

Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:

  • 1 - 0.12 = 0.88
  • 0.88 ^ 17 = 0.1138
  • 0.88 ^ 18 = 0.1001

Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.

  • 0.88 ^ 18 - 0.12 ^ 2 = X
  • 0.0857 = X

Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.

  • 0.12 ^ 6 x 0.88 ^ 12 = X
  • 0.0000000001 = X

Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.

Learn more about probabilities in brainly.com/question/25273534

3 0
3 years ago
3×-y=5,2×+y=5 pleaseplease ​
Tanya [424]

Answer:

x = 2

y = 1

Step-by-step explanation:

3x - y = 5..............(1)× 1

2x + y = 5...….......(2)× 1

3x - y = 5..............(3)

2x + y = 5.............(4)

Cancel y

3x + 2x = 5 + 5

5x = 10

Divide both sides by 5

x = 2

Substitute for the value of y

3x - y = 5

3(2) - y = 5

6 - y = 5

6 - 5 = y

1 = y

y = 1

6 0
3 years ago
Solve for u.<br> -22 = -8+2u
Leno4ka [110]
U=-7 hope that helps
4 0
3 years ago
Read 2 more answers
How many of these pitchers can a cylinder with height 9 inches and 2r fill? Explain how you know.
irakobra [83]

Answer:

4 pitches

Step-by-step explanation:

if a cylinder with height 9 inches and radius r is filled with water, it can fill a certain pitcher. how many of these pitchers can a cylinder with height 9 inches and radius 2r fill? explain how you know.

Solution:

The volume of a cylinder is given by:

V = πr²h;

where V is the volume, r is the radius of the cylinder and h is the height of the cylinder.

A cylinder with height 9 inches and radius r can fill a certain pitcher. Therefore the volume of the cylinder is:

V = πr²h = πr²(9) = 9πr²

V = volume of pitcher = volume of cylinder with radius r = 9πr²

For a cylinder with height 9 inches and radius 2r its volume is:

V2 = πr²h = π(2r)²(9) = 36πr²

Therefore, the number of pitchers a cylinder with height 9 inches and radius 2r can fill is:

number of pitches = 36πr² / 9πr² = 4

Therefore a cylinder with height 9 inches and radius 2r can fill 4 pitches.

3 0
3 years ago
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