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3 years ago

ILL GIVE brainleiest PLZ HELP

Mathematics

2 answers:

Vesnalui [34]3 years ago

7 0

The answer is c
10c + 5 45
you subtract 5 to both sides
10c 40
Divided 10 for both sides
c 4
it should be an open circle so it’s c

weqwewe [10]3 years ago

4 0

Answer:

Step-by-step explanation:

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What type of triangle is pictured in the following figure?

maks197457 [2]

This is an isosceles triangle. The angles in the legs are congruent therefore making the legs congruent as well. Hope this helps!

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3 years ago

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Help :( I suck at math

iris [78.8K]

Answer:

Step-by-step explanation:

For some side lengths to create a triangle, any two of the side lengths must have an added length together of less than the third leg. Otherwise, the vertices would simply not be able to be connected by the lines. In a), 3+5=8, but since it is not more, the triangle will not be able to be formed (it would basically just be a line.) In B, 7+8< 16. In C, there is the same situation as with the first example (4+15=19). Finally, in the last one, 5+7>12, and all of the side lengths work out. Therefore, the correct answer is D. Hope this helps!

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3 years ago

1/3x² + x+5/3x² = 1/9<br><br>HAHAHAHA......

mr_godi [17]

Answer:

Now, 3x 2+x+5⩾0

This is because b² −4ac=1−4×5×3

=−59 (roots are imaginary)

3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0

2x²+7x−4=0

2x²+8x−x−4=0

2x(x+4)−1(x+4)=0

(2x−1)(x+4)=0

x= 1/2 and−4 but x≥3

∴ No solution.

lol hehehe

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3 years ago

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Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo

natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

P(B) is the probability of the person having cancer, so $P(B) = 0.009$

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So $P(A/B) = 0.91$

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

$P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765$

What is the probability that the person actually does have cancer?

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213$

There is a 12.13% probability that the person actually does have cancer.

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3 years ago

The hypotenuse of a 45°-45°-90° triangle measures 18 cm. What is the length of one leg of the triangle?

lara31 [8.8K]

Answer:

The legs of a 45 45 90 triangle are congruent so if one leg is x we can write (using the Pythagorean Theorem):

x² + x² = 18²

2x² = 324

x² = 162

x = 9√2

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3 years ago