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4 years ago

Please help me with my math question!!!

Mathematics

1 answer:

Ierofanga [76]4 years ago

6 0

Answer:

2x^9(6x^3+x^2-4x+5x^-9)

Step-by-step explanation:

2x^9(6x^3+x^2-4x+5x^-9)

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Which of the following constants can be added to x^2 + 2/3x to form a perfect square trinomial?

Angelina_Jolie [31]

Hello.

A trinomial is a perfect square if the square root of the first term times the square root of the third term times 2 equals the middle term.

$\boxed{\mathsf{x^{2} + \dfrac{2}{3} x}}$

a) Adding 1/9:

$\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{1}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{1}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2}{3} x \rightarrow it \: is \: a \: perfect \: square \: trinomial}$

b) Adding 4/9:

$\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{4}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{4}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{2}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{4}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}$

c) Adding 4 and 1/9:

$\cdot \: \mathsf{x^{2} + \dfrac{2}{3} x + \dfrac{1}{9} + 4 = x^{2} + \dfrac{2}{3} x + \dfrac{37}{9}} \\ \\ \\ \mathsf{\sqrt{x^{2}} \times \sqrt{\dfrac{37}{9}} \times 2 =} \\ \\ \\ \mathsf{x \times \dfrac{\sqrt{37}}{3} \times 2 =} \\ \\ \\ \mathsf{\dfrac{2\sqrt{37}}{3} x \rightarrow it \: is \: not \: a \: perfect \: square \: trinomial}$

Hope I helped.

3 0

3 years ago

Jackson has 1 cup of butter. If he wants to use all the butter, how many batches of brownies can he make? Each batch of butter n

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

What number is a common multiple of<br>5 and 97?

solong [7]

Answer:

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100,105,110,115,120,125,130,135,140,145,150,155,160,165,170,175,180,185,190,195,200,205,210,215,220,225,230,235,240,245

Step-by-step explanation:

5 0

4 years ago

Pls help will mark brainliest

satela [25.4K]

Answer:

80in²

Step-by-step explanation:

Hey There!

So the first step of this problem is to find the width of the scale drawing

To do so we need to find the scale factor

To find the scale factor we divide the length of the room by the length of the scale factor

32/8=4

so the scale factor is 4

now to find the width

40/4=10

so the width of the scale drawing is 10 in

now we can find the area given the length and the width

10x8=80in²

so we can conclude that the area of the scale drawing is 80in²

4 0

3 years ago