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3 years ago

What number is a common multiple of5 and 97?

Mathematics

1 answer:

solong [7]3 years ago

5 0

Answer:

5,10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95,100,105,110,115,120,125,130,135,140,145,150,155,160,165,170,175,180,185,190,195,200,205,210,215,220,225,230,235,240,245

Step-by-step explanation:

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On Tuesday, Karen finished all her chores in 3/4 of an hour. On Wednesday, she finished her chores in 5/12 of an hour. How much

IRISSAK [1]

1 hour = 60 minutes

Tuesday: 60 divided by 4 = 15. Karen did it 3/4 of a hour so we multiply 15 by 4 which is 45. 45 equals 45 minutes. On Tuesday, Karen finished her chores in 45 minutes

Wednesday: first we divide 60 by 12 which is 5. 5 would equal 5 minutes. now we multiply 5 by 5 which is 25. Karen finished her chores in 25 minutes.

Answer: Karen finished her chores 20 minutes faster on Wednesday than Tuesday.

Hope this helps!

3 0

2 years ago

The product of 2x^2+6x-8 and x+3 in standard form

anzhelika [568]

Answer:

2x³ + 12x² + 10x - 24

Step-by-step explanation:

(2x² + 6x - 8)(x + 3) Distribute

2x³ + 6x² + 6x² + 18x - 8x - 24 Combine like terms

2x³ + 12x² + 10x - 24 This expression is in standard form

If this answer is correct, please make me Brainliest!

6 0

3 years ago

hi friends..please help me..it's very urgent... please give the solutions of the given bits... please....

Komok [63]

Hey I don’t know much of this but I really recommend you to re ask this question but choose the other option to talk to an expert :)

3 0

2 years ago

the maximum walking speed S, in feet per second of an animal can be modeled by the equation S=the square root gL where g=32ft/se

swat32

The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

<h3>Calculating Maximum speed</h3>

From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus

From the give information,

The maximum walking speed, S, is given by

S = √gL

Where g = 32ft/sec
and L is the length of the animal's leg

Thus,

For a Giraffe with a leg length of 6 feet

S = √32×6

S = √192

S = 13.856 ft/sec

For a Hippopotamus with a leg length of 3 feet

S = √32×3

S = √96

S = 9.798 ft/sec

Now, we will determine how many times greater 13.856 is than 9.798

13.856/9.798 = 1.41

Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus

Learn more on Calculating Speed here: brainly.com/question/15784810

#SPJ1

3 0

1 year ago

70 POINTS PLEASE HELP!! Use the two equations: f (x) =x^2 and g (x) =4x+1 to determine the solutions to the following function o

bagirrra123 [75]

<h2>My equation </h2>

f(x=x^2 is 30 and g(x) =4 1 is 50.1

Hope it helps #brainliestbunch =) 

6 0

3 years ago

What number is a common multiple of5 and 97?​

What number is a common multiple of5 and 97?