1. 7 : 07
2. 9 : 45
3. 6
4. 2 : 25
5. 8
6. 17
First you subtract 47 from both sides (-47 from 47 and -47 from 32)
Then you get -3x = -15
Divide -3 from -3x and -3 from -15
Leaving you with X = 5
Answer: m = -5/8
Step-by-step explanation:
The general equation for slope is rise over run, also known as:
m=(y2-y1)/(x2-x1)
From the points (x, y), we can get all the variables we need.
(-1, -7) gives us x1 = -1 and y1 = -7
(-9, -2) gives us x2 = -9 and y2 = -2
If we plug all the values in, we get:
m = (-2 - (-7))/(-9 - (-1))
m = (-2 + 7)/(-9 + 1) the negatives cancel
m = (5)/(-8)
m = -5/8
Explanation:
For the purpose of filling in the table, the BINOMPDF function is more appropriate. The table is asking for p(x)--not p(n≤x), which is what the CDF function gives you.
If you want to use the binomcdf function, the lower and upper limits should probably be the same: 0,0 or 1,1 or 2,2 and so on up to 5,5.
The binomcdf function on my TI-84 calculator only has the upper limit, so I would need to subtract the previous value to find the table entry for p(x).
The algebraic equation used to answer this question is:
3d + 4(1/2d) = 56.5
This is because he ran d, the distance, three times that week. For the rest of the four days, he ran 1/2 the distance, or half d.
To find the answer, you first distribute:
3d + 2d = 56.5
Add like terms:
5d = 56.5
Divide both side by 5:
5d/5 = 56.5/5
d = 11.3
On the first three days, Luke jogged 11.3 miles. On the remaining days, where he jogged 1/2d, Luke jogged 5.65 miles.
Hope this helps!
