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Maru [420]
3 years ago
7

There are 16 tables in the school lunch room each table can seat 22 students. How many students can be seated at lunch at one ti

me?
Mathematics
2 answers:
Alexandra [31]3 years ago
8 0
352 . If you multiply 16 by 22 it will give u an answer of 352
kondaur [170]3 years ago
5 0
352 you had to multiply
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What is an equation of the line that passes through the point (8, 2) and is parallel to
gayaneshka [121]

Answer:

x+4y is not change because it's parallel what changes is the result 8 + 4 × 2 = 16 so the equation is x + 4y = 16

4 0
2 years ago
Factor 2x^2 + 7x + 3
Vlad1618 [11]

Answer: (x - 3) (2x-1)

8 0
3 years ago
Read 2 more answers
Please explain how you got this answer.
Tema [17]
150 times

out of the first 5 cards, there is a 3/5 chance of drawing a yellow.
if you replace the card and draw again, you still have a 3/5 chance of drawing a yellow card.
keep doing this process for 250 draws, each draw will always have 3/5 chance of drawing a yellow card.

so 3/5 +3/5 +3/5 +...  (250 times) = 250 x 3/5 = 150

3 0
3 years ago
Pls help!!<br>These two polygons are similar. 4 2 9 o 15​
lina2011 [118]

Answer:

z = 3

Step-by-step explanation:

Similar polygons have the ratio of their corresponding sides equal to each other. There:

9/z = 6/2

Cross multiply

z*6 = 9*2

6z = 18

z = 18/6

z = 3

3 0
3 years ago
A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
polet [3.4K]

Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

(1) +s+=+42+

and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
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