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4 years ago

7

There are 16 tables in the school lunch room each table can seat 22 students. How many students can be seated at lunch at one ti

me?

2 answers:

Alexandra [31]4 years ago

8 0

352 . If you multiply 16 by 22 it will give u an answer of 352

kondaur [170]4 years ago

5 0

352 you had to multiply

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Write how many hundred thousands, ten thousands, and thousands there are in the numbers of acres of Land Big Bend National Park

sveta [45]

To solve this problem, we must remember our place values. 100,000 represents hundred thousands, 10,000 represents ten thousands, and 1,000 represents thousands similarly to how 100 represents hundreds, 10 represents tens, and 1 represents ones. Using this knowledge, we know that the number 8 is in the hundred thousands place, the number 0 is in the ten thousands place, and the number 1 is in the thousands place.

This means that there are 8 hundred thousands, 0 ten thousands, and 1 thousand in the number of acres of land the National Park owns.

Hope this helps!

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3 years ago

How many five-digit codes can be made if the first number cannot be a 0 or a 1 and no numbers can repeat?

Makovka662 [10]

Answer:

24,192.

Step-by-step explanation:

The first number must be one of 2,3,4,5,6,7,8 or 9. That is 8 possibilities.

The number of permutations of the other 4 numbers is 9P4

= 9! / (9-4)!

= 3024

Now we multiply by the 8:

3024 * 8

= 24,192.

6 0

4 years ago

The given series has six terms. What is the sum of the terms of the series? 10 + 20 + 30 + . . . + 60

Eduardwww [97]

10 + 20 + 30 + 40 + 50 + 60 = 210

5 0

4 years ago

Factor completely.

lidiya [134]

$9 \times {x}^{2} - 25 \\ = 9 {x}^{2} - 25 \\ = (3x - 5)(3x + 5)$

Answer is D.

Hope this helps. - M

4 0

4 years ago

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A plane is to be loaded with bottles of water and medical supplies to be sent to victims of an earthquake. Each bottle of water

Olegator [25]

Answer:

The vertex that maximize the problem is (2,000,4,000)

Step-by-step explanation:

we have

$z=10x+6y$

The vertex of the shaded region are

A(0,0), B(4,000,0),C(2,000,4,000), D(0,6,000)

Substitute the value of x and the value of y of each vertex in the z equation to find the solution

case A) A(0,0)

$z=10(0)+6(0)=0$

case B) B(4,000,0)

$z=10(4,000)+6(0)=40,000$

case C) C(2,000,4,000)

$z=10(2,000)+6(4,000)=44,000$

case D) D(0,6,000)

$z=10(0)+6(6,000)=36,000$

therefore

The vertex that maximize the problem is (2,000,4,000)

5 0

3 years ago

Read 2 more answers