X = 2 
If the mean of a positively skewed distribution is 122, which of these values could be the median of the distribution?
2 answers:
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Answer:
The answer is B. He spent 3 minutes eating lunch for every 10 minutes.
Step-by-step explanation:
He spent stuck inside during the brainstorm for:
20+18+12+10= 60 minutes in total.
And now we want to know what he did for every 10 minutes he spent in the rainstorm. To do that we need to divide what he did for every 10 minutes by the total of minutes that he was stuck:
And now we can multiply the time of the activities by 1/6 to get the time he did each activity every 10 minutes.
Reading:
minutes reading for every 10 minutes.
Eating:
minutes eating for every 10 minutes.
Watching TV:
minutes watching TV for every 10 minutes.
Drawing:
minutes drawing for every 10 minutes.
Therefore he spent 3 minutes eating lunch for every 10 minutes.
For Independent Events, P(A) × P(B) = P(A∩B)
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64
so we have, P(A∩B) = 0.4×0.1 = 0.04
P(A') = 1 - 0.4 = 0.6
This information can be represented on a Venn diagram as shown below
P(A'∪B) means the union of everything that is not A with everything that is B
P(A'∪B) = 0.06 + 0.54 + 0.04 = 0.64