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Mathematics

2 answers:

nordsb [41]2 years ago

4 0

Answer:

If the frame for the object is taller than the line of text in which it appears, text might overlap the imported image or you might see increased space above the line. Consider selecting a different anchored object position, inserting a soft or hard line break, resizing the inline object, or specifying a different leading value for the surrounding lines.

Step-by-step explanation:

this is what i could think of hope this helps

algol [13]2 years ago

3 0

Answer:

what do u mean

Step-by-step explanation:

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CALCULUS EXPERT WANTED

Vlad [161]

a. Use the mean value theorem. 16 falls between 12 and 20, so

$v'(16)\approx\dfrac{v(20)-v(12)}{20-12}=\dfrac{240-200}8=5$

(Don't forget your units - 5 m/min^2)

b. $v(t)$ gives the Johanna's velocity at time $t$ . The magnitude of her velocity, or speed, is $|v(t)|$ . Integrating this would tell us the total distance she has traveled whilst jogging.

The Riemann sum approximates the integral as

$\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600$

If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of $|v(t)|$ is determined by the value of $v(t)$ at each sample point, 200, 240, |-220| = 220, and 150.

c. Bob's velocity is given by $B(t)$ , so his acceleration is given by $B'(t)$ . We have