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Fantom [35]
4 years ago
10

Suppose you have a cache of radium, which has a half-life of approximately 1590 years. how long would you have to wait for 1/5 o

f it to disappear?
Mathematics
1 answer:
lubasha [3.4K]4 years ago
4 0
<span>You would have to wait 318 years for 1/5 (20%) of the Radium to disappear. 1590 is the point where half of the Radium would decay, so if you take 20% of that, it would equate out to 318 years. Radium has a long half life!</span>
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The function m(w) = –25w + 2500 models the amount of money in a safe, in dollars, w weeks after Lori learned the combination to
elena55 [62]

Answer:

B) There will be no money in the safe 100 weeks after Lori learned the combination.

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5 0
3 years ago
What is the value of x?
olga_2 [115]

Answer:

<x = 20°

Step-by-step explanation:

<x = 1/2(arc UT - arc SV)

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3 0
3 years ago
What is 23/40 as a percent? Show work please :)
dezoksy [38]

Answer: 57.5%

Step-by-step explanation:

Because....

23/40 =

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0.575 × 100/100 =

0.575 × 100% =

(0.575 × 100)% =

57.5%

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6 0
3 years ago
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A triangle has sides of length 48 mm, 5cm and 1.4 cm.
cricket20 [7]

Answer:

<u><em>The triangle is a right-angled triangle. </em></u>

Step-by-step explanation:

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5 0
2 years ago
Suppose that y varies directly as the square root of x, and that y=21 when x=361. What is y when x=247? (Round off your answer t
igomit [66]

Answer:

17.37

Step-by-step explanation:

y varies inversely as the square root of x

Mathematically:

y = k.root x

We first find k here

To find k, we were made to know that y is 21 and x = 361

k = y/root.x

k = 21/root. 361

k = 21/19

now what is y when x = 247

From y = k.root x

y = 21/19 * root 247

y= 21/19 * 15.72

y = 17.37

8 0
3 years ago
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