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3 years ago

What is 23/40 as a percent? Show work please :)

Mathematics

2 answers:

dezoksy [38]3 years ago

6 0

Answer: 57.5%

Step-by-step explanation:

Because....

23/40 =

23 ÷ 40 =

0.575 =

0.575 × 100/100 =

0.575 × 100% =

(0.575 × 100)% =

57.5%

* <em>Therefor, the correct answer would be 57.5% .</em>

<em>* Hopefully this helps:) Mark me the brainliest:)!!!</em>

lara31 [8.8K]3 years ago

6 0

Answer:

57.5%

Step-by-step explanation:

first divide 23 by 40

which is 0.575

then multiply 0.575 by 100/100 (it means 1 and is basically just 0.575 times 100%)

which comes out to 57.5

fun fact, if u want to know the decimal of something for example like 24% the decimal of that is .24, cos pretend that the little circle at the top of the line on the percent sign, is just a decimal point, and it rolls 2 digits to the left, so 384% would be 3.84...just a fun fact lol

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A computer and printer cost a total of $1284. The cost of the computer is three times the cost of the printer. Find the cost of

trasher [3.6K]

Answer: 3852

Step-by-step explanation:

1284 x 3 = 3852

4 0

3 years ago

Reposting because nobody will help me..

Llana [10]

Answer:

Step-by-step explanation:

18 = 2 * 3 * 3 = 2 *3²

$18*3^{(n+2)} = 2*3^{2}*3^{n+2}\\\\$

$= 2*3^{2+n+2}\\\\= 2*3^{n+4}\\\\= 2(3)^{n+4}$

Hint:

$a^{m}*a^{n} = a^{m+n}$

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3 years ago

Is -2.875 > -2 7/8?

Thepotemich [5.8K]

Answer:

The left side

−

2.875

is not greater than the right side

−

2.875

, which means that the given statement is false.

False

Step-by-step explanation:

8 0

4 years ago

Someone please be awesome and help me please :(

solong [7]

Answer:

$(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0$

$(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}$

$x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}$

Step-by-step explanation:

$x^2+\frac{b}{a}x+\frac{c}{a}=0$

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared. Whatever you add in, you must take out.

$x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

Now we are read to write that one part (the first three terms together) as a square:

$(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0$

I don't see this but what happens if we find a common denominator for those 2 terms after the square. (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

$(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0$