What is 23/40 as a percent? Show work please :)
2 answers:
You might be interested in
Answer: The 90% confidence interval for the population mean μ is between 82.85 and 85.15,
Step-by-step explanation:
When population standard deviation is not given ,The confidence interval population proportion is given by ( ):-
, where n= Sample size.
s= Sample standard deviation
= sample mean
t* = Critical t-value (Two-tailed)
As per given , we have
n= 64
Degree of freedom : df = n-1=63
s= 5.5
Significance level :
Two-tailed T-value for df = 63 and would be
(By t-distribution table)
i.e. t*= 1.669
The 90% confidence interval for the population mean μ would be
∴ The 90% confidence interval for the population mean μ is between 82.85 and 85.15,